Ohm's Law states Volts = Amps x Resistance.
You would need to apply 600 volts across 3 ohm load to have 200 Amps flow in circuit.
Not sure what you are really asking and why you mentioned 2 gauge.
I'm assuming this is standard residential single phase. Simple calculation as noted below: Watts / Volts = Amps So: 200 Watts / 120 Volts = 1.666~ Amps If you needed to calculate for a 220 volt run with the same 200 Watts 200 Watts / 220 Volts = 0.909~ Amps Remember 80% load per circuit breaker so a 15 amp breaker you should only load to 12 amps or less. Using Watt / Volts = Amps is the same as Amps x Volts = Watts. 15 Amps X .8 (80%) = 12 Amps max per circuit (for a 15 amp breaker/fuse) So 12 Amps x 120 Volts = 1440 Watts max for a 15 amp circuit (typical 14 gauge wire) *************************************************************** If a 20 amp circuit and 12 gauge wire (smaller gauge = larger dia wire). 20 Amps X .8 (80%) = 16 Amps max per circuit So 16 Amps x 120 Volts = 1920 Watts max for a 20 amp circuit (typical 12 gauge wire)
The formula to calculate the relationship between amps, volts and watts is Volts X Amps = Watts or Volts = Watts / Amps or Amps = Watts / Volts therefore; 200 Watts divided by 1.95 Amps is 102.5641 Volts.
No. For an example using a 3500 watt element. The amperage through the element will be I = W/E, 3500/120 = 29 amps. The resistance of this 3500 watt element will be R = E/I, 120/29 = 4.13 ohms. Now using the 200 volts and finding the amperage I = E/R, 200/4.13 = 48 amps. The new wattage of the element has become W = A x V, 48 x 200 = 9600 watts. The element will not stand the increase in amperage and will burn open. To operate on 200 volts and still have a 3500 element in the tank you will have to find an element with a resistance of 12 ohms. I = W/E, 3500/200 = 17 amps. R = E/I = 200/17 = 12 ohms. This is a resistance three times more than the 120 volt element to achieve the 3500 watt rating.
No, this should not be done. If the appliance is a heater it will operate over its given specified wattage. A 200 volt heater run off of 240 volt will have an output increase. Ohms law stated that current is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit. A 240 volt heater can be run off of a 200 volt supply but the wattage will be reduced. For example if the heater is 5000 watts at 200 volts, the current is I =W/E 5000/200 = 25 amps. The resistance of the heater is R = W/I (squared) =5000/25 x 25 (625) = 8 ohms. Applying 240 volts on the same heater whose resistance is 8 ohms results in this new heater wattage rating. W = E (squared)/R = 240 x 240 (57600)/8 = 7200 watts. This is 2200 watts higher than the manufacturer's safety rating. W = watts, I = amperage, R= resistance in ohms and E = voltage.
Watts = amps x volts. Amps = Watts/volts = 200/12 = 16.66.
0.2
1.36 volts Ohm's Law: Volts = Amps * Ohms
The Alpine v12 MRV-F505 amplifier puts out up to 200 watts of RMS power at 4 Ohms and using 12 volts. At 14 volts, it puts out up to 400 watts of RMS power with a bridged 4 Ohms ratio.
16.32 volts
5 ohms in parallel with 20 ohms is 4 ohms. 4 ohms across 200 volts is 50 amperes. However, resistance is a function of temperature, so the 4 ohms will probably be higher, reducing the current. How much depends on the temperature coefficient of the loads.
10 ma times 50 ohms is 0.5 volts. 0.5 volts is one two hundreth of 100 volts, so the multiplier resistor on 200 time 50, or 10,000 ohms.
Zero. Watts is the product of Amps x Volts. As you can see an amperage value is needed. Voltage = Watts/Amps. Volts = 200/? 20 volts
V = i*r v = 2 * 60 v= 120v
200
Remember Ohm's Law ; V = IR That is volts = amps(current) X Resistance. Algebraically rearrange R = V/I V = 20 volts I = 200 mA = 200/1000 Amps = 0.2 amps. Hence R = 20 V / 0.2 Amps R = 100 Ohms
I'm assuming this is standard residential single phase. Simple calculation as noted below: Watts / Volts = Amps So: 200 Watts / 120 Volts = 1.666~ Amps If you needed to calculate for a 220 volt run with the same 200 Watts 200 Watts / 220 Volts = 0.909~ Amps Remember 80% load per circuit breaker so a 15 amp breaker you should only load to 12 amps or less. Using Watt / Volts = Amps is the same as Amps x Volts = Watts. 15 Amps X .8 (80%) = 12 Amps max per circuit (for a 15 amp breaker/fuse) So 12 Amps x 120 Volts = 1440 Watts max for a 15 amp circuit (typical 14 gauge wire) *************************************************************** If a 20 amp circuit and 12 gauge wire (smaller gauge = larger dia wire). 20 Amps X .8 (80%) = 16 Amps max per circuit So 16 Amps x 120 Volts = 1920 Watts max for a 20 amp circuit (typical 12 gauge wire)
400 ohms