Following order of operations, multiplication happens first. Addition happens second.
7+6*42*2
=7+504
=511
if x2 + 7 = 37, then x2 = 29 and x = ±√29
(x2 + 14x + 49) = (x + 7)2
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
x2+14x+49 = (x+7)(x+7) when factored
-x2 + x + 42 = -[x2 - x - 42] = -[x2 - 7x + 6x - 42] = -[x*(x - 7) + 6*(x - 7)] = -(x - 7)*(x + 6)
x2 - 14x + 49(x - 7) (x - 7)
(x2+10x+21)/(x+3) = (x+7)
x2+6x-7 = (x+7)(x-1) when factored
x2 + 10x + 21 = (x + 3)(x + 7)
-x2 + x + 42= -x2 + 7x - 6x + 42= 7x - x2 + 42 - 6x= x(7 - x) + 6(7 - x)= (7 - x)(x + 6)
Given 3x3 + 4x2 +x + 7 is divided by x2 + 1, find the results:
A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}