x2 + 10x + 21 = (x + 3)(x + 7)
Factorising, we obtain, x2 + 10x + 21 = (x + 7)(x + 3). Thus, x2 + 10x + 21 / (x + 3) = x + 7. That's usually easier than dividing it out!
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.
x2+10x+21 = (x+3)(x+7) when factored.....
It is: x2-10x+21 = 0 and the value of x is 3 or 7 when solved
x2 + 10x + 21 = (x + 3)(x + 7)
x2+10x+21 = (x+3)(x+7)
Factorising, we obtain, x2 + 10x + 21 = (x + 7)(x + 3). Thus, x2 + 10x + 21 / (x + 3) = x + 7. That's usually easier than dividing it out!
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.
(x-7)(x-3)
x2+10x+21 = (x+3)(x+7) when factored.....
If that's + 10x + 21, the answer is (x + 7)(x + 3)
If that was - 10x + 21, it would factor to (x - 3)(x - 7) If that was + 10x + 21, it would factor to (x + 3)(x + 7) As it is, the solutions are irrational.
It is: x2-10x+21 = 0 and the value of x is 3 or 7 when solved
2x-3 = 21+10x 2x-10x = 21+3 -8x = 24 x = -3
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3