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# 7r plus 3 plus 2r - 2?

Updated: 9/18/2023

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Q: 7r plus 3 plus 2r - 2?
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### What does 12 plus 8r-6 equals 7r-5-3 equal?

12 + 8r - 6 = 7r - 5 - 3 8r +6 = 7r -8 r = -14

r+2

### R plus 3 plus 2r equals - 21?

r+3+2r=21 to solver this equation you have to first simplify then solve. you have to combine same variables. 3r+3=21 -3 -3 you subtract three to get r by itself (3r=18)/3 you divide by three to get r by itself Answer r=6

### Factor the polynomial -18r to the power of 3 plus 242r?

-2r(3r - 11)(3r + 11)

### What is 7-2r equals 13?

If: 7 -2r = 13 Then: r = -3

### 0.3 times 2r- 0.3 times3 equals 0.2r plus 0.9?

0.3(2r) - 0.3(3) = 0.2(r) + 0.9Clear parentheses:0.6r - 0.9 = 0.2r + 0.9Multiply each side by 10:6r - 9 = 2r + 9Add 9 to each side:6r = 2r + 18Subtract 2r from each side:4r = 18Divide each side by 4:r = 18/4 = 4.5

### When adding trinomials is the result always a trinomial?

Only if all the variables match up. Example of when they do match: 3x^2 +2y+r plus x^2- 2r+ 3y When they don't match: 3x^4+x+y plus 3x^3-x^2 +r

### What is 5r plus 7 equals 13 plus 2r plus 3r?

1)5r+7=13+2r+3r 2)5r+7=13+5r 3)5r's cancel 7=13 4)Subtract thirteen on both sides 7 =13 -13 -13 5)Answer is no solution because -6 doesn't equal to 0. -6=0 NO SOLUTION!!! Have fun with math!

### Use the identity below to complete the tasks:a3 + b3 = (a + b)(a2 - ab + b2)Use the identity for the sum of two cubes to factor 8q6r3 + 27s6t3.What is a What is b?

Below ^ denotes power. 8q^6r^3=(2q^2r)^3 denote as a^3 and find a=2q^2r 27s^6t^3=(3s^2t)^3 denote as b^3 and find b=3s^2t Now 8q^6r^3+27s^6t^3=a^3+b^3 = (a+b)(a^2-ab+b^2) | substitute back =(2q^2r+3s^2t)(4q^4r^2-6q^2rs^2t+9s^4t^2). Notice (2q^2r)^2=4q^4r^2 (3s^2t)^2=9s^4t^2. Hence 8q^6r^3+27s^6t^3=(2rq^2+3ts^2)(4r^2q^4-6rts^2t^2+9t^2s^4), a=2q^2r and b=3s^2t.

### What is the answer to 4x plus 8 equals 2r plus 20?

That depends on what the question is. What you gave is simply a relationship between two variables. You can simplify it like this: 4x + 8 = 2r + 20 (4x + 8) / 2 = (2r + 20) / 2 2x + 4 = r + 10 2x + 4 - 4 = r + 10 - 4 2x = r + 6 You can then solve for x by dividing both sides by two: 2x / 2 = (r + 6) / 2 x = r/2 + 3 You could also solve for r by subtracting six from both sides, and rearranging the equation: 2x = r + 6 2x - 6 = r + 6 - 6 2x - 6 = r r = 2x - 6 r = 2(x - 3)

43

### What is 3 plus 3 plus 3 plus 2?

3 + 3 + 3 + 2 = 11