2R = 2.5 inch x 3.5 inch
3p9
The same as the dimension of R
If 3p-5=9-4pthen 3p+4p=9+5=14then 7p=14and p=14/7so p=2Proof:(3 x 2)-5=19-(4 x 2)=1
12-2r = 10
3p-pq 2pr factorized = 1
2R = 2.5 inch x 3.5 inch
3p9
The same as the dimension of R
2 x r x r x r x s = 2r3s
Diameter = 2 x Radius Circumference = π x Diameter= π x (2 x Radius) 28.5 = π x 2R 28.5 / π = 2R 28.5/3.14159 = 2R = 9.0718 OR 9.1 Radius = 9.1/2 = 4.5 inches.
If 3p-5=9-4pthen 3p+4p=9+5=14then 7p=14and p=14/7so p=2Proof:(3 x 2)-5=19-(4 x 2)=1
pi x 2r
|2r + 9| = 5 So 2r + 9 = 5 or 2r + 9 = -5 so that 2r = -4 or 2r = -14 r = -2 or r = -7
About 3.14159 of them. (pi) The area of a circle is (pi)r2. The area of the square into which the circle can be inscribed is 4r2 or (2r x 2r).
12-2r = 10
The electron orbitals of silicon are 1s, 2s, 2p, 3s, and 3p. Silicon has a total of 14 electrons, with two electrons in the 1s orbital, eight electrons in the 2s and 2p orbitals, and four electrons in the 3s and 3p orbitals.