Total length = 16ft
Let the longer piece = x ft
Let the other piece = (16-x)ft
equation,
x - 2(16-x) = 1
x - 32 + 2x = 1
3x = 33
x = 11ft
16-x = 5ft
Longer piece = 11ft
shorter piece = 5ft
piece a has a greater length than piece b (a>b)
50" and 10" 60 = 5x + x = 6x; x = 10
Eight longAnswer:Two-by-four is a term applied to lumber with these dimensions (in inches) for its width and depth. The pieces are available in a number of lengths (6', 8', 16') as standard lengths and as shorter and longer pieces on special order.The two-by-four is actually 1 1⁄2 in × 3 1⁄2 in (38 mm × 89 mm).
Using algebra it works out that the lengths are 8.4 feet and 33.6 feet because 4*(8.4) = 33.6 and 8.4+33.6 = 42 feet
If a piece of wire was cut into 2 pieces in the ratio 7:8 and the shorter piece was 14cm, then the length of the longer piece will 16cm.
Longer: 6.75ft Shorter: 6.25ft
Write an equation and solve it. Call the length of the shorter piece "x", in this case, the longer piece is "3x". The sum of the two is equal to 116 inches.
81
Let the length of the shorter piece be x feet. Therefore, the length of the longer piece would be x + 1 feet. Since the total length of the ribbon is 9 feet, we can write the equation x + (x + 1) = 9. Solving this equation, we find that the shorter piece is 4 feet long and the longer piece is 5 feet long.
x the length of the shorter piece 3·x the length of the longer piece x + 3·x the length of the whole board = 4·x = 76" x = 76" / 4 = 19.
11 feet! y=2x+3 x+y=15 2x+3+x=15 3x=12 x=4 15-4=11 the two pieces are 4 feet and 11 feet
If you let x equal the short piece then 3x would be the long piece. x + 3x = 24 4x = 24 x = 6 3x = 18 So, the shorter piece would be 6 ft. and the longer piece would be 18 ft.