Answer is 48.
Step-by-step instructions:
Factors of 4 = 1,2,4.
Factors of 12 = 1,2,3,4,6,12.
So, let's see 12's first 4 multiples.
= 12,24,36,48.
Now, let's check 48's Factors.
= 1,2,3,4,6,12
It's Factors have both 4 and 12.
So, it is the number this is divisible by Both 4 and 12.
Not always because 30 is divisible by 2 and 6 but not by 12
No. Consider 6 itself or 18.
1, 2 and 3
This is 1 over 9. You just have to find out what number both 3 and 27 are divisible by and then divide each number by that until you have no other number both the numerator and denominator are both divisible by (they both have to be divisible by the same number to make it equivalent).
True
For any two numbers, there's always an infinite list of numbers that are divisible by both of them. For 93 and 273, one of them is 8463.
If a number is divisible by 14, it is also divisible by its factors, which are 2 and 7. This means the number can be evenly divided by both 2 and 7. Additionally, since 14 is a multiple of 1, any number divisible by 14 is also divisible by 1.
Any number that is divisible by both 2 and 3 is divisible by 6.
If a number is divisible by both 8 and 11, it will be divisible by 88.
The smallest number that is divisible by both 34 and 35 is 1,190.
30,030,003 is divisible by 9 without a remainder. Both 30,030,003 and 9 are odd numbers. Therefore, an even number such as 8 would always leave a remainder.
A number is divisible by 36 if it is divisible by both 4 and 9. For a number to be divisible by 4, its last two digits must form a number that is divisible by 4. For divisibility by 9, the sum of its digits must be divisible by 9. If a number meets both of these criteria, it is divisible by 36.