Answer is 48.
Step-by-step instructions:
Factors of 4 = 1,2,4.
Factors of 12 = 1,2,3,4,6,12.
So, let's see 12's first 4 multiples.
= 12,24,36,48.
Now, let's check 48's Factors.
= 1,2,3,4,6,12
It's Factors have both 4 and 12.
So, it is the number this is divisible by Both 4 and 12.
Not always because 30 is divisible by 2 and 6 but not by 12
No. Consider 6 itself or 18.
1, 2 and 3
This is 1 over 9. You just have to find out what number both 3 and 27 are divisible by and then divide each number by that until you have no other number both the numerator and denominator are both divisible by (they both have to be divisible by the same number to make it equivalent).
True
For any two numbers, there's always an infinite list of numbers that are divisible by both of them. For 93 and 273, one of them is 8463.
Any number that is divisible by both 2 and 3 is divisible by 6.
If a number is divisible by both 8 and 11, it will be divisible by 88.
The smallest number that is divisible by both 34 and 35 is 1,190.
30,030,003 is divisible by 9 without a remainder. Both 30,030,003 and 9 are odd numbers. Therefore, an even number such as 8 would always leave a remainder.
well any number is divisible by any other number, but 14 is divisible by both 7 and 2 and you get a whole number. 14 divided by 7 = 2 and 14 divided by 2 = 7
No. A prime number is divisible only by itself and 1. Squares have other factors.