The longer diagonal bisects the shorter diagonal.
Kites, arrowheads.
Diagonals of a rhombus are perpendicular so the product is the area. If x is the smaller diagonal, the longer is 4x, and the area if 4x2.
The diagonals are perpendicular to one another. The shorter diagonal is bisected by the longer diagonal. The kite is symmetrical about the longer diagonal. The longer diagonal bisects the angles at each end of the diagonal.
FG should be 12.2²-12²(half of 24)=4.84 then square root it which equals 2.2 and then you double it so the answer is 4.4
No, they do not. Only the longer diagonal bisects the shorter diagonal.
While only visualizing it and not bothering to draw it, it seems to us thatany diagonal of any regular polygon with more than 3 sides is longer thanany side.
A longer rhombus
Well, honey, let me drop some knowledge on you. In a rectangle, the diagonals are indeed longer than the sides, thanks to good ol' Pythagoras and his theorem. But in a square, the diagonals are the same length as the sides because all sides are equal. So, it really depends on the shape you're working with.
The height and longer diagonal do not provide enough information to calculate the sides.
A rhombus is NEVER equiangular. If it were equiangular it would no longer be a rhombus but a square.
Because if the shorter leg was shorter than the longer leg was long, then the longer leg wouldn't be longer than the shorter leg is short. The short leg would be the longer one rather than the long one being the short one.