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What is the area in terms of x of a rhombus with one diagonal that is 4 times the other diagonal?
Wiki User
∙ 11y ago
Diagonals of a rhombus are perpendicular so the product is the area.
If x is the smaller diagonal, the longer is 4x, and the area if 4x2.
Wiki User
∙ 11y ago
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How do you find the area of a rhombus?
Area = base x height.This formula also works for parallelograms, rectangles and squares.You find the area of a rhombus by multiplying l times h (length times height) where the height means the perpendicular distance from one side of length l to the other side.There are three ways to find the area of a rhombus, but these two ways are the easiest.You can use A = ba (base times altitude/height)You can use A= 1/2(d1d2) (1 half or 0.5 times diagonal 1 times diagonal 2)* * * * *The third option is s^2*sin(A) where s is the side length and A is an angle. It all depends on what information you are given.Area of Rhombus = length of first diagonal x length of second diagonal / 2
What is the diagonal measurement of a square 24 feet x 36 feet?
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
How do you calculate the area of a v kite?
The area of a v kite is 1/2 diagonal 1 times diagonal 2 :) hope this helps :D
What is the area and perimeter of a rhombus?
Area equals base times height. The perimeter is 4 times the length of one side.
If each side of a rhombus is doubled how much times will it's area increase?
It will increase to four times as much.
What is the area of a rhombus with diagonals of 12 and 5?
The diagonals bisect each other. Since that is true then the area of the rhombus is the sum of the two triangles. Half of one diagonal times the other diagonal.2(6x5)/2 or 6x5=30
What is the area of rhombus DEFG if DF is 10 and EF is 11?
If those are its diagonals then area is: 0.5*10*11 = 55 square units other wise use Pythagoras to find diagonal EG because area of a rhombus is 0.5 times the product of its diagonals.
How do you find the area of a rhombus?
Area = base x height.This formula also works for parallelograms, rectangles and squares.You find the area of a rhombus by multiplying l times h (length times height) where the height means the perpendicular distance from one side of length l to the other side.There are three ways to find the area of a rhombus, but these two ways are the easiest.You can use A = ba (base times altitude/height)You can use A= 1/2(d1d2) (1 half or 0.5 times diagonal 1 times diagonal 2)* * * * *The third option is s^2*sin(A) where s is the side length and A is an angle. It all depends on what information you are given.Area of Rhombus = length of first diagonal x length of second diagonal / 2
What is the perimeter of a rhombus when one diagonal is greater than the other diagonal by 10.5 cm and has an area of 67.5 square cm?
Let the diagonals be x+10.5 and x:- Area: 0.5*(x+10.5)*x = 67.5 Rearranging terms: x^2 +10.5x -135 = 0 Using the quadratic equation formula: x has a positive value of 7.5 Therefore diagonals are: 18 and 7.5 The rhombus will have 4 interior right angle triangles with sides of 9 and 3.75 Using Pythagoras' theorem each hypotenuse side is 9.75 Perimeter of the rhombus: 4 times 9.75 = 39 cm
How do you do cross cancellation?
Divide the numbers that are diagonal from each other, but there are times when this does not work.
How do you find the area of a rectangle from diagonal and 1 angle?
The diagonal multiplied by sin(angle) gives one side of the rectangle and the diagonal times cos(theta) gives the other. So the area is (diagonal)2 x cos(theta) x sin(theta).
What is the diagonal of a rectangle that is 20 feet on one side and 35 feet on the other?
Using Pythagoras; theorem the diagonal of the rectangle is 5 times square root of 65 or about 40 feet
What is thr area of the rhombus shown below AC 17 BD15 AB11.2?
Area of a rhombus: base times perpendicular height Or area of a rhombus: 0.5 times product of its diagonals
What is the formula for diagonal length?
you have to figure out length times width to get the formula for diagonal length suckers
How do you use the distance formula to prove the figure on the coordinate plane is a square?
You can use the distance formula to show that all four sides are the same length. The shape must, therefore, be a rhombus or square. If you then show that the length of the diagonal is sqrt(2) times the length of the side then, by Pythagoras, the diagonal and sides from a right angled triangle. The shape must, therefore, be a square.
What is the diagonal of a square that has a 16' side?
Using Pythagoras' theorem the diagonal is 16 times the square root of 2
Is the diagonal of a square the same as its side?
Not always, the diagonal can be figured out using the Pythagorean Theorem (a²+b²=c²). Where the diagonal is the hypotenuse (c). By rearranging the Pythagorean Theorem, you can see that the diagonal of a square is always 1.4 times the side of the square.
