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As the students can be split into 2, 3 or 5 groups with no students left over, the number of students in the classroom must be divisible by 2, 3 and 5.

Hint: Find a number which is a multiple of 2, 3 and 5.

The easiest way to find a multiple of any numbers is to just multiply them together:

2 x 3 x 5 = 30.

Other possible multiples of 2, 3 and 5 would include all multiples of this, namely 60, 90, 120, etc.

As it would be a classroom containing students, the most likely number would be the smallest multiple, namely 30.

Unpacking the maths behind this question, it is effectively asking:

What is the Lowest Common Multiple of 2, 3 and 5?

Which is, for example, an important consideration when adding or subtracting fractions - by using the Lowest common multiple it avoids the number getting too big and difficult to manage.

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Q: A Classroom of students can be formed into2 3and 5 groups with 0 students left over How many students are likely in the class Hint There are probably more than 20 studnets in a class show your work?
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