0
What else can I help you with?
How many different groups of 3 students can be formed if there are 20 students in the class?
20 x 19 x 18/3 x 2 = 1,140 groups
How many different groups of 5 students can be chosen from 23 students?
if order does not matter then, (23x22x21x20x19)/(5x4x3x2x1) = 33,649
How many different 3 member teams can be formed from a group of 6 students?
18
How many different groups of 48 cars can be formed from 50 cars?
only one with two cars left
How many different groups of 4 can be made from 17 students?
To find the number of different groups of 4 that can be made from 17 students, you can use the combination formula, which is given by ( C(n, r) = \frac{n!}{r!(n-r)!} ). In this case, ( n = 17 ) and ( r = 4 ). Therefore, the calculation is ( C(17, 4) = \frac{17!}{4!(17-4)!} = \frac{17!}{4! \times 13!} = \frac{17 \times 16 \times 15 \times 14}{4 \times 3 \times 2 \times 1} = 2380 ). Thus, there are 2,380 different groups of 4 that can be formed from 17 students.
How many different groups of 3 students can be formed if there are 20 students in the class?
20 x 19 x 18/3 x 2 = 1,140 groups
How many groups can be formed from 8 students at least 2 at a time?
There are 247 groups comprising 2 or more students.
How many different groups of 4 could be formed in a class of 23 students?
23 x 22 x 21 x 20/4 x 3 x 2 = 8,855 groups
How many different groups of 8 students can you create from a class of thirty students?
30C8 = 5,852,925
How many different groups of 5 students can be chosen from 23 students?
if order does not matter then, (23x22x21x20x19)/(5x4x3x2x1) = 33,649
How many different three-member teams can be formed from six students?
75
How many three member teams can be formed from a group of six students?
2 groups. 2 x 3= 6
How many different 3 member teams can be formed from a group of 6 students?
18
An algebra class of 21 students must send 5 students to meet with the principal How many different groups of 5 students could be formed from this class?
To find the number of different groups (a) within a larger group (b), use the formula b!/a!.(b-a)! where the ! sign indicates "factorial". In your problem b = 21 and a = 5 so we have 21!/(5!.16!) this simplifies to 21.20.19.18.17/5.4.3.2 cancelling leaves 21.19.3.17 ie 20349
How many different committees can be formed from 6 teachers and 33 students if the committee consists of 3 teachers and 2 students?
There are 10560 possible committees.
How many different groups of people of 25 people can be formed from 27 people?
There are 27 choose 25 ways, which is equivalent to 27! / (25!(27-25)!) = 351 possible different groups of 25 people that can be formed from a total of 27 people.
How many different groups of 48 cars can be formed from 50 cars?
only one with two cars left
