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A Rectangle has an area of 60 square feet. If its length is 2 feet more thank twice its width what are the dimensions of the rectangle?
Wiki User
∙ 15y ago
Area = 60Ft
Area = L x W
L = (2+2W)
Sub L into Area
60Ft = (2+2W)W
EXPAND
60Ft = 2W+2W^2
DIVIDE
30Ft = W+W^2
REARRANGE
W^2 + W - 30 = 0
QUADRATIC FORMULA
W = 5, -6
can't have a negative length, therefore 5
sub back into original equation
60ft = 5L
L = 12
check answer
L = (2+2W)
W = 5
(2+2(5)) = 12 = L
Correct
Wiki User
∙ 15y ago
itssoph ʚɞ
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