The first draw can be any one of 6 marbles.
The second draw can be any one of the remaining 5 marbles.
Total ways to draw 2 = (6 x 5) = 30 ways.
Successful draws can be:
1, 4
4, 1
2, 4
4, 2
2, 6
6, 2
3, 4
4, 3
5, 4
4, 5
6, 4
4, 6
= 12 possible successes.
The probability of success = (12/36) = 1/3 = 33 and 1/3 %
Things and numbers don't have probabilities. Situations and events that can happen have probabilities.
It is 7/36 = 0.1944... recurring.
The event space comprises the numbers 10 to 99, 90 such numbers. The favourable events are 15, 21, 27, ... , 99. There are 15 such numbers. So the probability is 15/90 = 1/6
There are (99 - 9) = 90 2-digit numbers.13 of them are multiples of 7.The probability is 13/90 = 14.4% (rounded)
The probability of an event, such as selecting a multiple of two from a set of numbers, depends on the size of the set and how many of those numbers are multiples of two. For example, in the set of integers from 1 to 10, there are five multiples of two (2, 4, 6, 8, 10). Thus, the probability P(multiple of two) in this case would be 5 out of 10, or 0.5. To determine the probability in a different context, simply apply the same principle by counting the multiples of two in the given set and dividing by the total number of elements in that set.
It depends on the number of numbers on the spinner and what those numbers are.
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
Things and numbers don't have probabilities. Situations and events that can happen have probabilities.
It is 7/36 = 0.1944... recurring.
First, you add all the numbers together- 5+6+4=15. So the number of red marbles (5) and the total number of marbles (15)= 5/15=1/3
6
The event space comprises the numbers 10 to 99, 90 such numbers. The favourable events are 15, 21, 27, ... , 99. There are 15 such numbers. So the probability is 15/90 = 1/6
There are (99 - 9) = 90 2-digit numbers.13 of them are multiples of 7.The probability is 13/90 = 14.4% (rounded)
The probability of an event, such as selecting a multiple of two from a set of numbers, depends on the size of the set and how many of those numbers are multiples of two. For example, in the set of integers from 1 to 10, there are five multiples of two (2, 4, 6, 8, 10). Thus, the probability P(multiple of two) in this case would be 5 out of 10, or 0.5. To determine the probability in a different context, simply apply the same principle by counting the multiples of two in the given set and dividing by the total number of elements in that set.
To find the probability of selecting a number from 20 to 30 that is divisible by 3, we first identify the numbers in that range: 21, 24, 27, and 30. There are four suitable candidates, so the probability of selecting one of them is 4 out of 11 (the total numbers from 20 to 30, inclusive). After replacing the selected number, we check which of these are divisible by 12. Among the numbers listed, only 24 is divisible by 12. Therefore, the probability of selecting a number divisible by 3 and then finding it divisible by 12 is 1 out of 11, which simplifies to approximately 0.0909 or 9.09%.
What is the probability of rolling an even with one roll of a numbers cube.
The probability is 17C4 = 2380