It depends on the number of numbers on the spinner and what those numbers are.
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Total number of possible stops = 8Number of successful stops = 2 (stops on 3 or on 6 are successful)Probability = 2/8 = 25%
The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.
To calculate the probability of spinning a multiple of 3 on a spinner labeled 1 through 10, we first determine the total number of favorable outcomes. The multiples of 3 between 1 and 10 are 3, 6, and 9. Therefore, there are 3 favorable outcomes. Since there are a total of 10 equally likely outcomes on the spinner, the probability of spinning a multiple of 3 is 3/10 or 0.3.
It is 1/6*1/6 = 1/36.
The probability is 0.625