Total number of possible stops = 8Number of successful stops = 2 (stops on 3 or on 6 are successful)Probability = 2/8 = 25%
The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.
If each of the numbers on the spinner is equally likely, then the answer is 0.3
It is 1/6*1/6 = 1/36.
The probability is 0.625
Total number of possible stops = 8Number of successful stops = 2 (stops on 3 or on 6 are successful)Probability = 2/8 = 25%
The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.
If each of the numbers on the spinner is equally likely, then the answer is 0.3
It is 1/6*1/6 = 1/36.
17 out of 21
75% probability
The probability is 0.625
The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.
It depends on how many sides the spinner has, a detail that was not provided in the question. If the spinner has 7 sides, and there is only one 3, then the probability of landing on a 3 is 1 in 7, or about 0.1429.
2/3
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.