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A ball is thrown with a speed of 20 ms at an angle 60 degrees above the horizontal how high does it rise?
Wiki User
∙ 14y ago
sin(60) =.866
20m/s*.866 = 17.32m/s in the vertical direction.
x=17.32t - 9.81t2
x=0 when the ball returns to its original height, so 17.32t = 9.81t2
17.32=9.81t
t=1.766sec for the ball to return to its original height. 1/2 this time will be its maximum height.
T=.883 sec.
maximum height = 17.32t - 9.81t2 = 14.4109 - 6.807 = 7.6039 m
Wiki User
∙ 14y ago
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