Another measurement could be 283-360 or -77* or 283+360 or 643*
Congruent angles have the same measure. congruent Kenpachi54 improve answer: Actually, angles don't have to be congruent just to have the same angle measurements A has a right angle is 90 degrees. even if there is a small right angle and a large right angle you know they are both 90 degrees because ALL right angles are 90 degrees, so there is really no name for it.
To have a congruent angle, the measure of the two angle must be the same, so if ABC is 15 degrees, then FDE would have to be 15 degrees also to be congruent.
No, because a complamentary angle just equals 90 degrees. An adjacent angle has a vertex and a common ray the same. If you have two angles that are not touching they cannot be adjacent because they dont have a same ray, but they may have a same vertex. If the two angles add up to 90 degrees they are complimentary and dont have to have anything the same. Hope this helps! If it is confusing look up what an adjacent angle is, then look up what a complamentary angle is! :)
Get some graph paper, draw two axes and bisect them with a 45 degree sloping line. Next pick any point on that 45 degree sloping line and from that point draw a line parallel to the horizontal axis so that it intersects the vertical axis. Do the same thing from the point drawing a line parallel with the vertical axis so that it intersects the horizontal axis. These two lines represent represent the components of your vector and if you measure them they will be of equal length and thus of equal magnitude. For ANY angle of slope (other than 45 degrees) the two vectors will not be of equal length.
20 degrees is a measure of angular displacement. This cannot be converted to lateral (horizontal) displacement.
It is an angular displacement of null value. The same as an angle of 0 degrees.
If you are looking to get an object up the highest, shoot it straight up. If you want to go for a specific horizontal displacement, use the range equation. R = v2sin(twice the launch angle)/ g. g is the gravitaional constant, 9.8 meters per second. Use degrees for the angle. v is the launch velocity. R is the horizontal displacement. This formula only works if your start altitude and end altitude are the same, i.e. you must shoot over a level field.
For the projectile to land at the same distance with the same initial speed, it must be launched at an angle of 15 degrees from the horizontal. This is because the range of a projectile is maximized when launched at a 45-degree angle. So, launching at 15 degrees in the opposite direction of 75 degrees should bring the projectile to the same landing point.
The question cannot be answered. i72 metres is a measure of linear displacement or distance whereas an angle is angular displacement. An angle is measured in degrees or radians, not units of length. If you extend the arms of the angle, the legnth between their ends will increase! Same angle, different length.
For a projectile launched at an angle θ, the range is the same for angles of θ and (90-θ) degrees. This is because the horizontal and vertical components of the initial velocity are the same for these angles, resulting in the same horizontal range.
The velocity is greatest at two points:1). when it leaves the hand of the tosser2). when it returns to the same height as it was when it was releasedThis answer is the same for any angle above horizontal, regardless of the angle.
The same as in a right angle which is 90 degrees
Work is maximum when the force applied is in the same direction as the displacement of the object. In this case, the angle between the force and displacement vectors is 0 degrees, resulting in the highest work done. This is known as positive work.
The direction of the applied force affects the amount of force that is doing work because work is the component of force that acts in the direction of the displacement. When the applied force is in the same direction as the displacement, all of it does work. If the force is at an angle to the displacement, only the component of the force parallel to the displacement does work.
Work = Force * displacement if the displacement and the force are parallel - work is positive if force and displacement are in the same direction, negative if they have opposite direction. At an angle Work = Force * displacement * cos(θ) where θ is the angle between the force and displacement vectors.
The magnitude of the vector at 45 degrees to the horizontal will be equal to the magnitude of its horizontal and vertical components. This is because the components are obtained by using trigonometric functions of the angle, and in this case, at 45 degrees, those functions yield the same value for both the horizontal and vertical components as the magnitude of the vector.