t matters how much mass the ball has
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
v2 = u2 + 2as where v = current velocity, u = initial velocity, a = acceleration, and s = displacement. Taking a = - 9.8 ms-2 v2 = 182 - (9.8 x 11 x 2) = 108.4 v = 10.4 ms-1
The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
An object thrown upward at an angle An object that's thrown horizontally off a cliff and allowed to fall
The equation for vertical motion is y = v0t + .5at2. y is vertical displacement v0 is initial vertical velocity a is acceleration (in meters, normal gravitational acceleration is about -9.8 m/s/s, assuming positive y is upward displacement and negative y is downward displacement)
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
There is no such thing as "interconversion of body" in this case. There are energy conversions; perhaps that's what you mean?
6.261 m/s
Objects fall to the ground because of the force of gravity.
Because of the force of gravity
9.8 meters per seconds squared in the downward direction.
9.8 m/s (2) Squared
mass of the object (times) gravitational acceleration (times) height the object reaches.
The answer for this question cannot be answered as we do not know how much force was applied to the ball for it to reach this height, alough for that height it would be around 3800 newtons
The volleyball will NOT hit the ground with greater anything. Assuming that the soccer ball is the same spherical diameter and greater mass than the volleyball it will hit the ground with greater velocity and greater impact.
because of the earths gravity, everything exept for helium filled balloons falls to the ground
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.