t matters how much mass the ball has
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
v2 = u2 + 2as where v = current velocity, u = initial velocity, a = acceleration, and s = displacement. Taking a = - 9.8 ms-2 v2 = 182 - (9.8 x 11 x 2) = 108.4 v = 10.4 ms-1
The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
An object thrown upward at an angle An object that's thrown horizontally off a cliff and allowed to fall
The equation for vertical motion is y = v0t + .5at2. y is vertical displacement v0 is initial vertical velocity a is acceleration (in meters, normal gravitational acceleration is about -9.8 m/s/s, assuming positive y is upward displacement and negative y is downward displacement)
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
The speed of a ball thrown upward upon striking the ground will be the same as the speed at which it was thrown, but in the opposite direction. The speed of a ball thrown downward upon striking the ground will be faster than the speed at which it was thrown due to the acceleration from gravity.
There is no such thing as "interconversion of body" in this case. There are energy conversions; perhaps that's what you mean?
Objects fall back to the ground when thrown upward due to the force of gravity acting upon them. Gravity is a force that pulls objects towards the center of the Earth, causing them to accelerate downwards. When an object is thrown up, it loses its upward velocity and gravity then pulls it back towards the ground.
When a basketball is thrown upward, it is acted upon by gravity, which pulls it back down towards the ground. As it moves upward, its velocity decreases until it reaches its peak height and momentarily stops, then gravity causes it to accelerate back downward due to the force of gravity.
The initial velocity of the ball is 16 feet per second when thrown upward. The velocity decreases as the ball travels upward due to gravity until it reaches its peak and starts to fall back down.
9.8 m/s (2) Squared
The speed of the ball is greatest when it is thrown upward and decreases as it reaches the peak of its trajectory. The speed continues to decrease as the ball falls back down due to the force of gravity pulling it towards the ground.
Things thrown upward fall back to the ground due to the force of gravity, which pulls objects towards the Earth's center. As the object rises, its speed decreases until the pull of gravity overcomes the upward force and causes it to fall back down.
The volleyball will NOT hit the ground with greater anything. Assuming that the soccer ball is the same spherical diameter and greater mass than the volleyball it will hit the ground with greater velocity and greater impact.
When a ball is thrown upward, it experiences a brief period of acceleration while moving against the force of gravity. Once the ball reaches its peak height, it begins to fall back down due to gravity.
When an object is thrown upward, work is done against gravity as the object moves upward. The amount of work done is equal to the force applied to lift the object multiplied by the distance it moves vertically.