The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
4ft*Ns=H
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
At any time 't' seconds after the ball is released,until it hits the ground,h = 5 + 48 t - 16.1 t2
H= -1/2gt2+vt+s Where H is the ending height g is the rate of gravity (32 ft/sec2 or 9.8 m/sec2) t is the time v is the initial velocity and s is the starting height.
To find the initial velocity of the kick, you can use the equation for projectile motion. The maximum height reached by the football is related to the initial vertical velocity component. By using trigonometric functions, you can determine the initial vertical velocity component and then calculate the initial velocity of the kick.
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
To calculate the time it takes for the arrow to hit the ground, we need to consider the vertical motion of the arrow. The time taken for an object to fall back to the ground can be determined using the kinematic equation: h = (1/2)gt^2, where h is the initial height, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time. In this case, the initial velocity is upwards, so the initial height will be 0. Using the equation, we can determine the time it takes for the arrow to hit the ground.
To find height in physics, you can use the equation: height initial velocity squared / (2 acceleration due to gravity). This equation is derived from the principles of kinematics and the laws of motion. By plugging in the values for initial velocity and acceleration due to gravity, you can calculate the height of an object at a certain point in time.
To answer this question one would need to know the rock's initial height and velocity.
To determine the maximum height reached by an object launched with a given initial velocity, you can use the formula for projectile motion. The maximum height is reached when the vertical velocity of the object becomes zero. This can be calculated using the equation: Maximum height (initial velocity squared) / (2 acceleration due to gravity) By plugging in the values of the initial velocity and the acceleration due to gravity (which is approximately 9.81 m/s2 on Earth), you can find the maximum height reached by the object.
4ft*Ns=H
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
The height attained by an object projected up is directly proportional to the square of its initial velocity. So, if an object with initial velocity v attains a height h, then an object with initial velocity 2v will attain a height of 4 times h.
Increasing the initial velocity of a projectile will increase both its range and height. Higher initial velocity means the projectile will travel further before hitting the ground, resulting in greater range. Additionally, the increased speed helps the projectile reach a higher peak height before it begins to descend back down.
The initial velocity of the bullet can be obtained by using the kinematic equation for projectile motion. Assuming we neglect air resistance, the initial velocity of the bullet fired vertically upward from a gun can be calculated by setting the final velocity as 0 when it reaches the maximum height of 7000 ft. Using the equation v^2 = u^2 + 2as, where v is the final velocity (0 m/s), u is the initial velocity, a is the acceleration due to gravity, and s is the total displacement. Solve for u to find the initial velocity of the bullet.