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A boy throws a rock straight up in the air It reaches the highest point of its flight after 2.5 seconds how fast was the rock going when it left the boys hand?
Shanna4444
There is no way to tell unless a height is specified. Once you have that, you would divide the distance (height) by the time (2.5). Suppose 50 feet, and it took 5 seconds to reach that height.
You would have 50/5 = 10 feet per second.
given the acceleration of gravity is 9.81m/s2 and y=at2 then ymax = 9.81(2.5)2 OR 61.3125m
At its highest point it has a velocity of zero. if 0=v0-at and a=9.81 and t=2.5 then
v0 = 9.81(2.5) = 24.525 m/s
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