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Acceleration of the arrow is -3m/s2

A = (velocity minus initial velocity) / time

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Q: An arrow in flight has an initial velocity of 65 meters per second and 10 seconds later it has a velocity of 35 meters per second Which is the acceleration of the arrow?
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If An arrow in flight has an initial velocity of 65 meters per second and 10 seconds later it has a velocity of 35 meters per second Which is the acceleration of the arrow?

Magnitude of average acceleration = (change of speed) divided by (time for the change)Average 'A' = (35 - 65) / 10 = -30/10 = -3.5 meters per second2-- That's the average over the 10 seconds. We don't know anything about thevalue of the acceleration at any particular instant during the 10 seconds.-- We're working entirely with scalars ... speed, not velocity, and magnitude ofacceleration ... since we don't know anything about the arrow's direction at anytime during the whole event.


A rocket gose from 0 m per second to 560 m per second in the first 7 seconds of flight What is your acceleration?

a = m/s/s a = 560/1/7 a = 80m/s/s


How can vectors be applied to real life situation?

You use it when throwing an object at a target. Over any but a trivially short distance, gravity will pull the object downwards. So you aim higher than the target. To hit the target, the vector sum of the initial velocity and the downward acceleration experienced during the flight must be a vector aimed directly at the target.


A boy throws a rock straight up in the air It reaches the highest point of its flight after 2.5 seconds how fast was the rock going when it left the boys hand?

There is no way to tell unless a height is specified. Once you have that, you would divide the distance (height) by the time (2.5). Suppose 50 feet, and it took 5 seconds to reach that height. You would have 50/5 = 10 feet per second. given the acceleration of gravity is 9.81m/s2 and y=at2 then ymax = 9.81(2.5)2 OR 61.3125m At its highest point it has a velocity of zero. if 0=v0-at and a=9.81 and t=2.5 then v0 = 9.81(2.5) = 24.525 m/s


A stone is projected with a velocity of 58.8 ms at an angle of 30 degree from horizontal find the Time of flight maximum height and horizontal range?

A stone is thrown with an angle of 530 to the horizontal with an initial velocity of 20 m/s, assume g=10 m/s2. Calculate: a) The time it will stay in the air? b) How far will the stone travel before it hits the ground (the range)? c) What will be the maximum height the stone will reach?

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If An arrow in flight has an initial velocity of 65 meters per second and 10 seconds later it has a velocity of 35 meters per second Which is the acceleration of the arrow?

Magnitude of average acceleration = (change of speed) divided by (time for the change)Average 'A' = (35 - 65) / 10 = -30/10 = -3.5 meters per second2-- That's the average over the 10 seconds. We don't know anything about thevalue of the acceleration at any particular instant during the 10 seconds.-- We're working entirely with scalars ... speed, not velocity, and magnitude ofacceleration ... since we don't know anything about the arrow's direction at anytime during the whole event.


How do you find time of flight from initial velocity and an angle at which an object is thrown?

If you're willing to ignore the effect of air resistance, then the answer is as follows: The object's horizontal velocity remains constant (at least until it eventually hits the ground). The vertical component of the object's initial velocity ... call it V(i) ... is the (total initial velocity) multipled by the (sine of the initial angle above the horizontal). Beginning at the time of the toss, the magnitude of the vertical component of velocity is V = V(i) - 1/2gT2. T = number of seconds after the toss g = acceleration of gravity = approx 32 ft/sec2 or 9.8 m/sec2


If a plane accelerates at 1000 km per hr south as soon as it starts its trip down the deck for take off how fast is the plane going 1.5 seconds later as it leaves the flight deck?

Use the equation v= u + at where v= final velocity, u= initial velocity, a= acceleration and t= time. Here the inital velocity; u is 0 km/ hr because the plane started from rest; the acceleration, a is 1000 km/ hr; time, t is 1.5 seconds which could be converted to hours to make the solution simpler (1.5 seconds= 1.5/3600 hours). Using the equation v= u +at, v= (o km/hr) + (1000 km/hr)(1.5/3600 hours) v= 0 + (1500/3600) km/ hour v= 0.42 km/ hour


What will the velocity and acceleration be of a ball at its highest trajectory point just before it starts to fall?

The acceleration of the ball (after it leaves the thrower's hand) is the acceleration due to gravity, g.1 The vertical velocity of the ball at its apex is zero. The horizontal velocity is constant throughout the ball's flight; it is whatever it was at the outset of its arc.2 ---------------- 1. The acceleration due to gravity, g, is -9.8 m/s2 or -32.2 ft/s2. 2. Ignoring the effects of air resistance, which tend to slow things down.


If a moving bodycomes to restthen its acceleration is-?

To come to rest, its velocity must change, therefore it will accelerate. Once it is at rest, if it remains at rest, it will no longer accelerate, i.e., its acceleration will be zero.


You shoot an arrow into the air. Two seconds later the arrow has gone straight upward to a height of 33.0 m above its launch point. What is the arrow's initial velocity?

The acceleration of gravity is [9.8 meters per second2] directed downward.After two seconds of vertical flight, the upward speed of the arrow is (9.8 x 2) = 19.6 m/sless than its initial velocity.Average speed = 1/2 (Vi + Vf) = 1/2 (Vi + Vi-19.6) = Vi - 9.8Distance = (average speed) x (time) = 33(Vi - 9.8) x (2) = 33Vi - 9.8 = 16.5Vi = 16.5 + 9.8 = 26.3 m/s


If you have Microsoft Flight Simulator X and Microsoft Flight Simulator X Acceleration can you install Microsoft Flight Simulator X Deluxe Edition?

There is no need to buy Microsoft Flight Simulator X: Deluxe Edition as Microsoft Flight Simulator X: Acceleration contains everything from Microsoft Flight Simulator X: Deluxe Edition and more.


What is flight acceleration?

IN flight sim the Flight Acceleration mode is used to make the game move faster (similar to fast forward) This is ok in the normal flight mode but is NOT acceptable in the multi flight i.e. on IVAO etc


How many seconds was the record of a chicken flight?

13 seconds thats not what i call a flight : )


Does the acceleration of the object change while it is in flight?

Since the velocity of an object is composed of its speed and its direction, then an object under the influence of Earth's gravity will always be changing velocity. If it is near the surface, its speed is slowing down if it is moving vertically up, or speeding up if it is moving vertically down. If it is moving horizontally, its speed is slowing because of air friction. But even when it is in a circular orbit and its speed is not changing, the direction in which it is moving is constantly changing. so its velocity is constantly changing. Since we have no information on what the flight is, there is no useful answer.


If skylar throws the football 50 meters in 3 seconds what is the average speed (velocity) of the football?

The average speed is 16.66... (repeating) metres per second. It is not possible to calculate the average velocity without further information because, due to gravity, the velocity is changing continuously during the ball's flight.


A bullet is fired horizontally with an initial velocity of 500ms at a target located 200m from the rifle Using the approximate value of g equals 10ms squared how far does the bullet fall in this time?

It takes the bullet (500/200) = 2.5 seconds of horizontal flight to reach the target.Under the influence of gravity for 2.5 seconds, ignoring air resistance, it will fall(1/2 G) (t)2 = (5) (6.25) = 31.25 meters