The number is eleven
ANSWER
First of all we want the unknown # or x to be left by itself so ?=x
x-4=8+(x/5)
-8 -8
x-12=x/5
*5 *5
5x-60=x
-5x -5x
-60=-4x
/-4 /-4
15=x
I believe it is 15 not 11
substitute x for 11 and 15...
try- 11-4=8+(11/5)
11-4=10+(1/5)
7=10+(1/5) ???
try- 15-4=8+(15/5)
11=8+3
11=11
it works this way
Purely physical: depends on the number of particles rather than on the kind of them.The number influences e.g. the boiling point elevation (decreased volatility), osmotic pressure (increased osmolality), etc.
an isotope is a different form of that element. They just have different mass numbers/ atomic mass. Therefore having the same characteristics of the atom except for an increased/decreased number of neutrons. Isotopes have the same atomic number as each other.
As increase in proton number, the attraction from nucleus towards electrons increased. This will pull the electrons stongly. So, the size/ atomic radius decreased across the d-block.
It has to do with what types of channels are open during this phase. In the repolarization phase the number of potassium channels are increased and the number of sodium channels are decreased. This allows for action potentials to not occur. Otherwise, the action potentials would add up and produce tetany.
Increased number of protons in the nucleus.
A quotient is the number obtained when one number is divide by another. 11 decreased by 10 is 1. The only number that can be paired with -9 to obtain a quotient of 1 is -9.
x - 2 = 7 + x/4 4x - 8 = 28 + x 3x = 36 x = 12
if the quotient of -20 and 4 is decreased by 3
So let's call the number we are looking for x. x-4 is the number decreased by 4 quotient of the number and 5 is x/5 so x-4=8+ x/5 we have 5x-20=40+x and 4x=60 so x=15 Let's try it? 15-4=11 8+15/5=11
x-4=8+x/5 5(x-4)=5(8+x/5) 5x-20=8+x 4x=28 x=7
11-9=v
87
It has decreased.
Increased
If a fraction's denominator is increased, the number gets smaller. If a fraction's denominator is decreased, the number gets bigger.
. This is same as half of r.
r/2-8