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The inner circle of the track with radius r meters and circumference 2πr is jogged in a time of Tseconds.
The outer circle of the track has radius r + 3 and circumference 2π(r + 3) and is jogged in a time of T + 12.
Speed = Distance ÷ Time.
2πr/T = 2π(r + 3)/(T + 12) : r(T + 12) = T(r + 3) : 12r = 3T : 4r = T
Substituting for T in Speed = 2πr/T gives : Speed = 2πr/4r = π/2 meters per second.
π/2 mps = π x 60 x 60/(2 x 1000) = 5.655 kph (3dp)
The jogger runs at 5.655 kph
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