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A cliff diver plans to jump off a cliff into a river and needs to know the velocity with which she will strike the water. it takes a rock 2.5 seconds to reach the water. what'ld her final velocity be?
Wiki User
∙ 14y ago
80 ft / sec ~ 55mph
The above ignores air resistance which will not be significant at this speed.
Wiki User
∙ 14y ago
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A sharp cliff caused by sudden movements along dip-slip faults is called a .?
A sharp cliff caused by sudden movements along dip-slip faults is called an earthquake. It causes the ground to shake for several seconds.
A ball of mass m rolls off a cliff of height h with a horizontal velocity v it reaches the ground with vertical speed of?
If one assumes air resistance to be negligible, then: final velocity = sqrt( g * 2 * h ) where g is 9.8 metres per second per second. The quantities v and m do not matter, because gravitational acceleration does not depend on mass (all objects fall at the same rate) and because the horizontal velocity is independent of the vertical velocity.
What is cliff in a sentence?
Cliff is a noun in a sentence. There are a few examples on how to say cliff in a sentence below. Cliffhanger was hanging from a cliff. The cliff proved to be dangerous.
Make a sentence of word cliff?
Cliff Richard is the best. the cliff
What is the impact velocity of a rock thrown horizontaly from a cilff?
The impact velocity of a rock thrown horizontal from a cliff depends on two things, the initial speed of the rock (vi) and the height of the cliff (h). The final velocity (impact velocity) is represented by vfFor this formula, air resistance is neglected, and acceleration due to gravity is assumed to be 9.8 m/s2. The acceleration is positive here because down is being treated as the positive direction. You will get the same result if you use negative 9.8 m/s2 and make the height negative. sqr() means square root.vf = sqr(19.6h + vi2)For example if the rock was thrown off a 3 meter high cliff at 20 m/s, the impact velocity would be sqr(19.6 x 3 + 202), which would be sqr(58.8 + 202), which would be 21.42 m/s.The angle relative to the ground is the inverse tangent of sqr(19.6h)/viwhich in this case is tan-1( sqr(19.6 x 3)/20), which is tan-1(7.67/20) which is 21.0 degrees.
A diver jumps from a 48ft cliff into the ocean with an initial velocity of 8 seconds when does he hit the water?
"8 seconds" is not a velocity.
A squirrel drops a nut over a cliff what is the velocity of the nut after 3 seconds?
Ignoring air resistance, the velocity of any object that goes off a cliff is 29.4 meters (96.5 feet) per second downward, after 3 seconds in free-fall.
A stone is thrown horizontally at 8 ms from a cliff 78.4 m high how far from the base of the cliff will the stone strike the ground?
According to the Laws of Physics, Horizontal Velocity is unaffected by Vertical Velocity. Thus you need to first find how long it will take the stone to hit the ground. Assume: Acceleration due to gravity = 9.8 m/s^2 Velocity due to gravity = 9.8x m/s, where x is seconds Displacement due to gravity = 9.8x^2 m, where x is seconds Set Displacement = to 78.4m 78.4m = 9.8x^2 m and solve for.. x = sqrt(8) = 2 sqrt(2) Then to find displacement horizontally, multiply time*velocity horizontally distance from base of cliff = (2 sqrt(2))s * 8 m/s = 16 sqrt(2) m
What does initial velocity means?
initial velocity is the velocity with which a particle starts its journey.
A rock is thrown from a cliff and hits the ground 5 seconds later at a distance of 50 meters from the cliff How high was the cliff?
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
A rock is dropped from a cliff and hits the ground 6.0 seconds later How high is the cliff?
176.4 meters
If a Rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 3 seconds in ms if it encounters no air resistance?
speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s
A monkey runs off the edge of a cliff He hits the water below 5m from the base of the cliff How fast was he running if the cliff was 10m high?
There are two major steps in solving this problem. First, we have to figure out how long it takes a monkey to fall 10m. Second, we divide the distance from the base of the cliff by the number of seconds to estimate the unfortunate simian's velocity. To get the time the monkey falls, (assuming this is on Earth with gravitational acceleration equal to 9.8 m / s), use the equation d = 4.9t2 . t = sqrt(d/4.9). Filling in the given value for d (10m) we get t = sqrt (10/4.9) which is about 1.43 seconds. If the monkey travelled outward 5m from the edge of the cliff in 1.43 seconds, the furry fellow was going 5m / 1.43s or about 3.5 m/s. Why the monkey chose to do the Acapulco Cliff Dive remains a mystery known only to him, and he is not talking.
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff. How fast was the ball thrown?
If the ball ended 40 m from the cliff after 4 seconds, the original horizontal velocity was 10 m/s. You can calculate the height assuming standard gravity acceleration (g = 9.81 m/s2) and zero original vertical velocity, by calculating the final downward velocity vy2, vy2 = a x t = 9.81 m/s2 x 4 s = 39.24 m/s and from this the average velocity, vav = 39.24 m/s / 2 =19.62 m/s and multiply by 4 s, 19.62 m/s x 4 s = 78.48 m.
A ball is dropped from a cliff and has acceleration of 9.8ms2 How long will it take the ball to reach a speed of 22.8ms?
The objective is to calculate the final velocity of 22.8m/s. We can use the formula v = u+at v is th final velocity u is the initial velocity which is equal to 0 in this case a=9.8m/s2( given) t is the time for achieving the final velocity 22.8 = 0+9.8 t t=22.8/9.8 t=2.3 seconds
A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How far form the base of the cliff does the ball strike the ground?
64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).
A ball is thrown horizontally at 20 meters from the top of a cliff 50 meters high How far from the base of the cliff does the ball strike the ground?
64 METERSA+
