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There are 6 rolls for the die times 2 possibilities for the coin, so there are 12 total possibilities. Because there is a 1/2 chance of flipping a head, the answer is half of 12, or 6.

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Q: A die is rolled and a coin is tossed how many have heads as the coin result?
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Related questions

If you tossed a coin 1000 times what is the probability the 785th toss is heads?

The number of times a coin is tossed does not alter the probability of getting heads, which is 50% in every case, as long as the coin has not been rigged (i.e., a double-headed coin, a weighted coin) to alter the result.


What is this answer a coin is tossed and a number cube is rolled Find P heads then greater than 4?

With one toss of a coin, there can be at most 1 head. So the probability of 4 or more heads is very definitely 0.


What is the probability that I'll get heads on the next toss if I tossed a coin fifteen times and got heads twelve?

The odds are 50/50. A tossed coin does not have a memory.


How many orders can heads and tails be tossed when a coin is tossed 3 times?

Eight.


What is the probability that when a coin is tossed it will land heads up?

50%


What is the probability that a coin tossed in the land with heads up?

It is 0.5


What is the probability of a coin tossed two times to get heads?

It is 3/4


What are the odds if a coin is tossed 3 times and the out come is heads?

The answer depends on "the outcome is heads HOW MANY TIMES!"


If a die is rolled and a coin is tossed what is the probablity of obtaining a head and a 5?

1 in 12 chance


If a coin was tossed 1000 times what would be the probability that coin will land on heads?

1/2 or 0.5


If a coin is tossed for 30 times what is the probability of having 10 heads?

10 :)


What are the odds in favor of getting 2 heads when a coin is tossed twice?

One in four. 1:4. The probability of getting heads when a fair coin is tossed is: P(H) = 1/2. The probability of getting heads on a second toss is: P(H) = 1/2, this result is independent of the result of the first toss. The probability of having both events happen (heads on the first and heads on the second toss) is: P(H1UH2) = (1/2)∙(1/2) = 1/4 = 0.25 = 0.25%