well, it will have 6 times of the greater chance.
50%
Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.
The answer depends on "the outcome is heads HOW MANY TIMES!"
The probability is 0.5
These are all independent events. So the probability of them all happening is the product of the probabilities of each one of them happening. The desired probability is (2/6)*(1/2)*(1/2)=1/12
The number of sequences is 27 or 128.
well, it will have 6 times of the greater chance.
Coins do not have numbers, there is only the probability of heads or tails.
Eight.
The odds are 50/50. A tossed coin does not have a memory.
mean = 5, variance = 5
The number of times a coin is tossed does not alter the probability of getting heads, which is 50% in every case, as long as the coin has not been rigged (i.e., a double-headed coin, a weighted coin) to alter the result.
50%
It is 0.5
Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.
It means that if the coin were tossed an infinite number of times, half of the tosses would come up heads and half would be tails.