Since , V = u + at,
we get , a = v - u /t
= 402.3 - 0 /9.013
= 44.6355264617 ms-2
Therefore, acceleration = 44.6355264617 ms-2
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
aSsuming constant acceleration, and movement along a line, use the formula: vf2 = vi2 + (1/2)at2 (final speed squared equals initial speed squared plus one-half times acceleration times time squared).
Assuming that your units of velocity are in units/second Acceleration = (velocity 2 - velocity 1) / time Acceleration = (4.9 - 0) / 3 Acceleration =1.63 *With correct significant figures the answer is 2
You can use the formula for distance covered:distance = (initial velocity) x (time) + (1/2) (acceleration) (time squared) Solve for time. This assumes constant acceleration, by the way. If you assume that the initial velocity is zero, then you can omit the first term on the right. This makes the equation especially easy to solve.
Assuming that acceleration is constant during that time, just divide the change in speed by the time.
Acceleration is a change in velocity. Assuming a constant direction, if you're speeding up that is positive acceleration. If you are slowing down, that's negative acceleration. Either way you are accelerating.
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
Assuming (a) an initial velocity of zero, and (b) constant acceleration, the formula becomes: distance = 0.5 at2 (distance = 1/2 times acceleration times time squared).
You push a 12.3 kg shopping cart with a force of 10.1 N. a) What is the acceleration of the cart.
From the formula force = mass x acceleration, if there is more mass, there will be less acceleration. Assuming the force doesn't also change.From the formula force = mass x acceleration, if there is more mass, there will be less acceleration. Assuming the force doesn't also change.From the formula force = mass x acceleration, if there is more mass, there will be less acceleration. Assuming the force doesn't also change.From the formula force = mass x acceleration, if there is more mass, there will be less acceleration. Assuming the force doesn't also change.
aSsuming constant acceleration, and movement along a line, use the formula: vf2 = vi2 + (1/2)at2 (final speed squared equals initial speed squared plus one-half times acceleration times time squared).
Newton's Second Law: force = mass x acceleration, or acceleration = force / mass. NOTE: That's the MASS, not the weight. If you really know an object's weight (in newton), you need to divide by 9.8 first (assuming standard gravity), to get its mass in kilograms.
I guess you mean the centripetal acceleration in its orbit around the Sun. That's not something that will usually be found in references such as the Wikipedia, but you can calculate it in several ways. 1) Use the law of gravitation to calculate the force between an object of mass 1 kg. at Mercury's distance from the Sun, and the Sun. Any other mass will do as well, but after calculating the force, you need to calculate the acceleration, so the mass of Mercury (or another object at the same distance) cancels in the calculation. 2) Look up Mercury's orbital data. Assuming a circular orbit, calculate the centripetal acceleration as v2/r.
The vehicle accelerates, assuming the engine is in a vehicle.
Gravity produces acceleration on an object, assuming that no other force acts on the object.
Acceleration is the CHANGE in velocity; you're assuming CONSTANT velocity. So the acceleration is zero.
Assuming the mass remains constant, the acceleration will be tripled as well.