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if he has 100 dollars, and can only buy 100 animals, then he can buy 76 chickens for $38, 21 Pigs for $42, and 4 sheep for $20. :)

well that's 101, but im close. and i did it all by myself. :D

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Q: A farmer has 100 and can buy 100 animals so how many of each animal can he buy if chickens are 50 cents pigs 2 and Sheep 5?
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Sheep cost 15 dollars chickens cost 1 dollar and mice are .25 cents how many of each do you need to have 100 animals and spend 100 dollars you must have at least one of each animal?

3 Sheep 15 = 45 41 Chickens @ 1.00 = 41 56 Mice @ .25 = 14


Is the set of cats a part of the whole set of farm animals?

No Because Horses, Chickens, Sheep, Ducks, and Geese are only farm animals.Thank You Hope This Helps.... Good Luck


Is sheep an adverb?

No. Sheep are animals, and the word sheep is a noun. It is the same plural as singular (sheep).


If sheep cost 2 dollars pigs 1 dollar and hens 50 cents what are three solutions involving all animals if a farmer were to spend 10 dollars on 10 animals?

1 could be 10 pigs. 2 could be 6 hens, 1 pig and 3 sheep. 3 could be 1 pig, 6 hens and 3 sheep, (same as above :) ) HOPE THIS HELPED


One sheep farmer tells another farmer Give me one of your sheep and I will have the same The other farmer says Give me one of yours and I will have twice as many as you How many sheep do they have?

An Algebra ProblemThe qualifier that their herds will be the same size with the transfer of 1 tells you there is a 2 sheep difference between the herd sizes. Farmer A has 2 less than Farmer B. The next part says that moving one sheep to the larger herd creates a 2-to-1 size ratio of the herds. With 1 more sheep, Farmer B will have 2 times Farmer A.For the equality, if Farmer A and Farmer B loses 1 , then (A+1) = (B-1), creates the relationship B = A+2Letting the smaller herd size be A, the larger herd is A+2.And the transfer of 1 sheep creates the equality A+1 = (A+2)-1The second equation says that the larger herd (presently A+2) will be twice as big as the smaller herd A if A loses 1, becoming (A-1), while the second herd becomes (A+2)+1 or A+3. This creates the formula 2(A-1) = A+3This solves to [2A-2 = A+3] and [2A = A+5] and A = 5The first farmer has 5 sheep, and the second farmer has 7 sheep.-------------In standard algebraic form, the equations are :[ x + 1 = y - 1 ] or y = x + 2y+1 = 2(x-1)Substituting, (x+2)+1 = 2(x-1) and x = 5

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