The volume of displaced water for a metal cylinder with a volume of 50cm3 is: 13,210 US gallons of water or 11,000 UK gallons of water.
The volume of any cylinder is (pi) x (radius of the circular end)2 x (length of the cylinder)
First of all, if you're going to work with the volume of displaced water, it makes no difference at all how much water you start out with. The object would displace the same amount from a bucket as it would from Lake Michigan. But, to deal with the answer to your question: It's not possible to answer your question. The volume of water displaced is the same as the volume of the metal that you drop into the bucket. But you've only told us the area of one flat side of the metal. We have no idea what its volume may be until we also know its thickness.
The volume of the piece of metal is measured by the difference in the volume of water in the graduated cylinder before and after the piece of metal is placed in the cylinder. This is stated to be 36 - 20 = 16 mL. Density is defined to be mass per unit volume. Therefore, for this piece of metal the density is 163/16 = 10 g/mL. (Only two significant digits are justified, because the is the number of significant digits in the limiting datum 16.)
Density = mass/volume = 167g/ (volume displaced) = 167g / (36mL - 20mL) = 167g/16mL = 10.4g/mL. Density is usually recorded in g/cm3 which is the same as g/mL so the density is 10.4g/cc. Also, to be extra correct, the answer should be rounded to 10g/cc because 16mL only has 2 significant figures so that is the number you report in your final answer.
There are several methods that can be used to calculate the density of a metal ball. The density of a metal ball can be derived from the fact that the volume is: 4*(pi)*r^3/3 and the denisty is mass/volume. If the mass and moment of inertia are known but the dimensions of the metal ball are not, then you can use the fact that the moment of inertia of the ball is 2m*r^2/5 and solve for m to get r=(5I/2)^.5 and plug in the value for r into the volume equation then calculate the density of the ball by dividing the mass by the calculated volume.
The reading on the graduated scale is taken before and after the metal is lowered into the cylinder . The second reading is subtracted from the first. This gives the volume of the metal in cubic centimetres.
The volume of any cylinder is (pi) x (radius of the circular end)2 x (length of the cylinder)
The volume of the metal cylinder is 21.4mL - 15mL = 6.4mL. This is the water displacement method for determining the volume of an irregular solid.
You'd use a "Eureka can!" If you fill a cup or special container completely full and submerge the object you want to measure in the water then water will be displaced by the object. If you collect the water and measure it in a measuring cylinder then you will have the volume of water displaced, which will be exactly the volume of the object. The "Eureka can!" is named because of Archimedes discovery or displacement and density which allegedly caused him to run naked down the street shouting "Eureka" in celebration.
Hydrogen is displaced from acid when you add a reactive metal.
First of all, if you're going to work with the volume of displaced water, it makes no difference at all how much water you start out with. The object would displace the same amount from a bucket as it would from Lake Michigan. But, to deal with the answer to your question: It's not possible to answer your question. The volume of water displaced is the same as the volume of the metal that you drop into the bucket. But you've only told us the area of one flat side of the metal. We have no idea what its volume may be until we also know its thickness.
1357.2
The basic formula for density is density = mass/volume. If you have mass and density, you can manipulate the formula so that volume = density x mass.
Well, first you need to gather more information. Density= Mass/Volume, so you will need to find the mass in grams of this metal pipe and then calculate the volume. I am assuming that the pipe is going to be a nice even cylinder, so use the circular cylinder volume formula. Then, divide mass/volume, and your answer will be in g/cm3.
Air bubbles would make the volume you read in the measuring cylinder increase from the actual volume of theliquid. so when you add in the metal, there would be an increase in the volume of the metal than it really is. the mass of the metal cannot be affected by air bubble because this is the amount of matter in the metal. This increase in volume causes the density of the metal to reduce from its original value. since mass is constant, density is inversely proportional to volume. As volume increases, density decreases.hope that was helpful.
20cm3
The volume of the piece of metal is measured by the difference in the volume of water in the graduated cylinder before and after the piece of metal is placed in the cylinder. This is stated to be 36 - 20 = 16 mL. Density is defined to be mass per unit volume. Therefore, for this piece of metal the density is 163/16 = 10 g/mL. (Only two significant digits are justified, because the is the number of significant digits in the limiting datum 16.)