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56, 55, 54, 53, 52, 51, 50

Q: A number has more than one tens the value of the tens digit is 50the ones digit in the number is less than 7what are the possible numbers?

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As a product of its oprime factors: 2*5*7 = 70

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The answer is; that's your assignment question, don't cheat - especially in writing.

-241 * * * * * Actually, the answer is 13*(-18) + 7 = -227 The remainder is ALWAYS positive. Thus -227/13 = (-234+7)/13 = -234/13 + 7/13 = -18 + 7/13

3k-5=7k+73k-7k=7+5-4k=12k=-3

7, 49, 343, 2401 are the first 4 powers of 7. The 7 - 9 - 3 - 1 sequence repeats for each further 4 powers so 7 to the 48th will end in 1 and 7 to the 50th will end in 9.

It is 10.Think of it this way:30=3*10=3*2*5=2*3*570=7*10=7*2*5=2*5*7What they both have in common is 2 and 5.2*5= 10