T= Time, h=height, g= gravity
Formula T=Sqr.rt (2h/g)
Given=
T=.350s
g=9.8
1. .350=Sqr.rt(2h/9.8) (raise both sides to the second power)
2. .350^2=Sqr.rt(2h/9.8)^2 ( this will equal to)
3. .1225=2h/9.8 ( multiply both sides by 9.8)
4. 1.2005=2h (divide both sides by 2)
5. .60025=h (answer)
... and what is the question? The second ball should arrive at the floor a second after the first, both should have the same speed.
if you ignore air resistance, it would take about 3.5 seconds; at ttat point where it hits the ground it is traveling at 75 mph. Because of the air drag, it may take a bit longer to hit the ground.
There is no such thing as a 4 dimensional figure. Three dimensional objects are measured in length, width, and height. In physics the 4th dimension is used as time when discussing relativistic consequences. But how do you draw 'time'? If you do then you ignore at least one of the other dimension (length, width, or height) and use time in its place.
50m/s. The kinetic energy (movement energy) of the ball when it leaves the gun is gradually converted into gravitational potential energy as it moves up and slows down. Eventually it reaches its highest point and stops. It has zero kinetic energy, all the energy has been converted into gravitational potential. The ball then starts to fall under gravity. The gravitational potential energy is converted back into kinetic energy. No energy is lost so the ball arrives back where it started with the same kinetic energy it left with or to put it another way at the same speed it left. If you do not ignore air resistance it arrives back a bit slower and the physics gets much much more complicated..........
they ignore it. because they are stupid
Not if you can ignore air resistance, it doesn't.
If you can ignore air resistance, they're not. Neither component has any influence on the other one unless the object is acting as an airfoil.
The horizontal velocity will be equal to the translational velocity of the ball right before it falls off the table. ============================== When we do exercises that deal with the behavior of the ball after it leaves the edge of the table, we always ignore air resistance. When we do that, the horizontal component of velocity remains constant forever, or at least until the ball hits something.
Yes - but only if you can ignore air resistance, that is, if the objects fall for a sufficiently short time, and have a sufficiently high mass, and sufficiently small surface area, so that air resistance becomes insignificant.Yes - but only if you can ignore air resistance, that is, if the objects fall for a sufficiently short time, and have a sufficiently high mass, and sufficiently small surface area, so that air resistance becomes insignificant.Yes - but only if you can ignore air resistance, that is, if the objects fall for a sufficiently short time, and have a sufficiently high mass, and sufficiently small surface area, so that air resistance becomes insignificant.Yes - but only if you can ignore air resistance, that is, if the objects fall for a sufficiently short time, and have a sufficiently high mass, and sufficiently small surface area, so that air resistance becomes insignificant.
If you ignore air resistance, then they will reach their maximum height at the same time. In order not to ignore air resistance, you would need to know their shapes.
If you ignore air resistance, weight has no effect at all.
The maximum speed of a fired projectile, unless fired downward in a vacuum, is the muzzle velocity - this is when the propulsive acceleration ceases. Ignoring air resistance, the projectile would maintain its horizontal velocity, while gravity would first reduce then restore the vertical component. Terminal velocity, the maximum possible atmospheric speed, is determined by mass, gravity, air density, and projectile shape, as gravitic acceleration is slowed by air resistance.
Since the velocity is constant due to the fact that there are no external forces acting in the horizontal direction, if you neglect air resistance, therefore, the horizontal velocity of a projectile is constant.
The 'x' component of the velocity is usually the label given to the horizontalcomponent. Also, remember, we generally ignore air-resistance in this typeof exercise. When we do that, there is no horizontal force on the object, sothe horizontal component of velocity can't change.The only force on the object is gravity, and that's completely vertical, so onlythe vertical component of velocity can change.
In the usual simple treatment of projectile motion, the horizontal component of the projectile's velocity is assumed to be constant, and is equal to the magnitude of the initial (launch) velocity multiplied by the cosine of the elevation angle at the time of launch.
A strictly structured change process often ignores the ingrained human resistance to change.
The initial velocity of the football can be easily found by solving for the magnitude of the vector formed by adding the two components given. This is accomplished using the Pythagorean theorem. The initial velocity of the football is approximately 26.2 m/s.