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There are numerous solutions to the formula A + BA + C = A + BC, some of them are:

* (0,1,1) * (5,2,10) * (4,5,5) * (7,8,8) * (3,4,4) * (6,3,9)

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Q: A plus BA plus C equals A plus BC?

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(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c

4

You could conclude that B lies between A and C.

1+x=dd+x so dd=1 so d=1 1+x=89b+x so 89b=1 so b=1/89 bc+x=1+x so bc=1 so c=1/(1/89) = 89 so cd=89 (and x=88)

Because there is no way to define the divisors, the equations cannot be evaluated.

Related questions

(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c

4

f = B x C

the answer is a

A Line Bisector

A + bc - c + ba

(b + 2c)(b - c)

You could conclude that B lies between A and C.

(a+b+c) 2=a2+ab+ac+ba+b2+bc+ca+cb+c2a2+b2+c2+2ab+2bc+2ca [ ANSWER!]

1+x=dd+x so dd=1 so d=1 1+x=89b+x so 89b=1 so b=1/89 bc+x=1+x so bc=1 so c=1/(1/89) = 89 so cd=89 (and x=88)

Because there is no way to define the divisors, the equations cannot be evaluated.

a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)