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Q: What is the simplified solution to BC plus 0 equals f?

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BC' + BC' = 2BC'

yes because ab plus bc is ac

Commutativity.

x = 0.125 ( BC - 7 )

associative? single replacement

Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?

There are numerous solutions to the formula A + BA + C = A + BC, some of them are: * (0,1,1) * (5,2,10) * (4,5,5) * (7,8,8) * (3,4,4) * (6,3,9)

It does bc 69 is awesome

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It would be a straight line of length bc

bc - 2d is in its simplest form.

This is a 'Sngle Displacement' reaction ( A + BC --> AC + B

(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c

It is the property of commutativity.

bc equals st multiplied by the scale factor.

Anything you like (as long as it is > -16 so that BC > 0). In a parallelogram, adjacent sides do not impose any restrictions on one another.

That depends on the value of CD and the perimeter of the quadrilateral out lined in the question

(b + 2c)(b - c)

You could conclude that B lies between A and C.

1+x=dd+x so dd=1 so d=1 1+x=89b+x so 89b=1 so b=1/89 bc+x=1+x so bc=1 so c=1/(1/89) = 89 so cd=89 (and x=88)

Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc

If point b is in between points a and c, then ab +bc= ac by the segment addition postulate...dont know if that was what you were looking for... but that is how i percieved that qustion.

Single displacement reactions follow the form A + BC equals AC + B. Because the sodium and the hydrogen switch places, this reaction is considered single displacement.

The square root of 149 (7 squared plus 10 squared equals 149).

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