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- (a+b+c) 2=
- a2+ab+ac+ba+b2+bc+ca+cb+c2
- a2+b2+c2+2ab+2bc+2ca [ ANSWER!]

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A = 9 B = 10 C= 19

Q: A plus b plus c whole square?

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(a+b+c)²=a²+b²+c²+ 2ab+2bc+2ac

C Square

1.774225a

Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.

it's the bit in the square root sqrt of (b squared minus 4ac) when a,b and c are the values belonging to the equation ax(sqared) plus bx plus c

Related questions

(a+b+c)²=a²+b²+c²+ 2ab+2bc+2ac

(a+b-c)2 = a2 + b2 +c2 +2ab - 2bc - 2ac

C Square

If you mean (a-b+c)^2, then... a^2 - ab + ac - ab + b^2 - bc + ac - bc + c^2 = a^2 + b^2 + c^2 - 2ab + 2ac - 2bc.

1.774225a

b+b+b+c+c+c+c =3b+4c

b + b + b + c + c + c + c = 3b + 4c

Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.

Yes.

It's the square root of a2+b2. It cannot be simplified. It is NOT a+b. The answer is c square.

Because it is mathematically incorrect. a^2 + b^2 = c^2 Take square root of both sides. SQRT (a^2 + b^2) = c So you see, it is not a plus b equal c.

a3 + b3 + c3 + 2(a2)b + 2(b2)c + 2(a2)c + 2ab2 + 2(c2)b +abc