24 feet square feet
A 6 by 4 rectangle will have a perimeter of 20 units
You multiply the length by 2 (because there are two sides of the rectangle that have that measure). You then subtract that number from the perimeter. The number you will be left with is twice the width, so you divide that by two and you get the width of the rectangle.
If the length and width of a rectangle are multiplied by the same number, then . . . -- the perimeter is multiplied by the same number -- the area is multiplied by the square of the numbner
Because the perimeter is lenght + length +width +width, you do perimeter - double the width, and then halve the remaining number. that should give you the length.
i think that it si 4x3 and it eqals 12
A 6 by 4 rectangle will have a perimeter of 20 units
You multiply the length by 2 (because there are two sides of the rectangle that have that measure). You then subtract that number from the perimeter. The number you will be left with is twice the width, so you divide that by two and you get the width of the rectangle.
If the length and width of a rectangle are multiplied by the same number, then . . . -- the perimeter is multiplied by the same number -- the area is multiplied by the square of the numbner
Because the perimeter is lenght + length +width +width, you do perimeter - double the width, and then halve the remaining number. that should give you the length.
the answer to number 20 is B...12
i think that it si 4x3 and it eqals 12
There is no relationship between the perimeter and area of a rectangle. Knowing the perimeter, it's not possible to find the area. If you pick a number for the perimeter, there are an infinite number of rectangles with different areas that all have that perimeter. Knowing the area, it's not possible to find the perimeter. If you pick a number for the area, there are an infinite number of rectangles with different perimeters that all have that area.
18cm is the area and perimeter. the width is 3cm.
Select any number, W, between 0 and 4 units.Consider a rectangle with width W and length, L = 8 - W units.Then the rectangle with dimensions L and W will have a perimeter of 16 units.Since there are infinitely many possible values for W, there are infinitely many possible answers to the question.
the old perimeter is 17 * 2 The old perimeter = 38
if the perimeter is 12 then the semi perimeter is 6 p=2L+2w 12=2L+2w by division 6=L+w
You can't tell the dimensions from the perimeter. There are an infinite number of different rectangles, all with different lengths and widths, that all have the same perimeter.