i think that it si 4x3 and it eqals 12
You forgot to put in the length of the rectangle's perimeter.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
7 x 19 cm
Length = 9 Width = 9 Your rectangle is a square.
If the given dimensions are the length and width of a rectangle then its perimeter is 15.6+4.5+15.6+4.5 = 40.2
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
You forgot to put in the length of the rectangle's perimeter.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
The dimensions of the rectangle will then work out as 14 cm by 10 cm because the perimeter is 14+10+14+10 = 48 cm
the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
7 x 19 cm
Length = 9 Width = 9 Your rectangle is a square.
If the given dimensions are the length and width of a rectangle then its perimeter is 15.6+4.5+15.6+4.5 = 40.2
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
The dimensions of a rectangle are the length and the width. With these two measurements , the area of the rectangle can be calculated : Area = length x width. The perimeter can also be found : Perimeter = (2 x length) + (2 x width).
No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)