Q: How can you get a rectangle with whole-number side length's and a perimeter of 20 meters?

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Perimeter of a rectangle = twice (length + width), in this case 22 m.

22 meters.

The perimeter is 42 metres.

Perimeter of rectangle: 24+17+24+17 = 82 meters

28

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To find the perimeter of the rectangle you add up all the sides. There are two lengths and widths for every rectangle, so you know the length is 40 meters x 2 = 80 meters. Perimeter is the total length of all the sides so you just minus 120 from the two lengths which is 80. So the width is 40, divide 2 (2 widths) = 20 meters. Width = 20 meters OR if they're asking for widthS then it'll be 40 meters, but they're not.

The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar

what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters

Perimeter of a rectangle = twice (length + width), in this case 22 m.

Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters

40 meters.

The perimeter would be 28 meters.

As a rectangle has four sides then 11 + 4 + 11 + 4 = 30 meters perimeter

Perimeter = 4*267 = 1068 meters

54 Meters

22 meters.

The perimeter is 42 metres.