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A rock dropped on the moon will increase its speed from 0 ms its starting speed when first dropped to 49 ms in about 3 seconds What value do you calculate for the magnitude of the acceleration o?
Wiki User
∙ 12y ago
Acceleration = (change in speed) divided by (time for the change).
From the figures given in the question, the acceleration is ( 49/3 ) = 16.33 m/sec2 .
There's no way that this is happening on the moon. That acceleration is about 67% greater
than the acceleration of gravity on the earth's surface. It should be about 83% less, or about 1.63 m/sec2.
I see the problem now. The '49' in the question should be '4.9'.
apex- 1.63 m/s2
Wiki User
∙ 12y ago
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A rock dropped on the moon will increase its speed from 0 ms its starting speed when first dropped to 4.9 ms in about 3 seconds What value do you calculate for the magnitude of the acceleration o?
1.63 m/s2
How do you calculate acceleration from velocity?
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
Calculate percentage increase from 18 to 23 percent?
There is a 5% increase. (23 - 18)If you meant the percentage increase from 18 to 23. It is a 27.77% increase.percentage increase = ( a - b ) / aa = larger ending numberb = smaller starting number
The vector has a magnitude of 11 and a direction of 20 degrees. What is the magnitude of the x component?
Assuming the 20 degrees are measured counterclockwise, starting from the x-axis (this is more or less standard), you can calculate the x-component as 11 x sin(20). Make sure your calculator is set to degrees first.
What is the percent increase from 10 to 25?
to calculate the percent increase . first = 25 - 10 = difference between the two numbers = 15 then divide this differnece by the original starting number (which is 10)= 15 divided by 10 = 1.5 to make this a percent increase multiply by 100 . so you result is 1.5 x 100 = 150% to summarise: ((final number- starting number) / starting number) x 100 = percent increase
A rock dropped on the moon will increase its speed from 0 ms its starting speed when first dropped to 4.9 ms in about 3 seconds What value do you calculate for the magnitude of the acceleration o?
1.63 m/s2
What is the starting point when you divide the amount of increase by it to calculate the rate of increase?
Base
How do you calculate acceleration from velocity?
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
Calculate percentage increase from 18 to 23 percent?
There is a 5% increase. (23 - 18)If you meant the percentage increase from 18 to 23. It is a 27.77% increase.percentage increase = ( a - b ) / aa = larger ending numberb = smaller starting number
The vector has a magnitude of 11 and a direction of 20 degrees. What is the magnitude of the x component?
Assuming the 20 degrees are measured counterclockwise, starting from the x-axis (this is more or less standard), you can calculate the x-component as 11 x sin(20). Make sure your calculator is set to degrees first.
What is the percent increase from 10 to 25?
to calculate the percent increase . first = 25 - 10 = difference between the two numbers = 15 then divide this differnece by the original starting number (which is 10)= 15 divided by 10 = 1.5 to make this a percent increase multiply by 100 . so you result is 1.5 x 100 = 150% to summarise: ((final number- starting number) / starting number) x 100 = percent increase
How do you calculate voltage drop for starting motor current and how to get the starting pf?
How do you calculate voltage drop for starting motor current
How can recognize acceleration?
Acceleration is a change in speed or velocity. So if you going faster than your starting speed your accelerating. If your changing direction (a change in velocity) then that is also acceleration.
Difference between static and dynamic charercteristic of motor?
I think you are talking about the study of the electrical system for motor starting in ETAP (or any such software). Here are the answers:1. When do we use Static and Dynamic motor starting?If you know the Motor torque characteristics, Load torque characteristics and the inertia information of the motors, bearings and loads, you can do the Dynamic motor starting study. Otherwise, do the Static motor starting study - it simply needs the starting time and the locked rotor current of the motor.2. What is the difference between the two?(1) The Dynamic motor starting develops the motor starting current characteristics based on the motor starting torque, load torque and the inertia, while the starting current remains flat at locked rotor current during the starting time for Static acceleration. (See the previous posting http://cr4.globalspec.com/thread/42981 , comment # 2 for detail how the starting time is calculated for Dynamic acceleration).(2) Dynamic starting acceleration requires additional data than the Static acceleration.(3) The Dynamic acceleration calculates the acceleration time and current from the input data, while the Static acceleration assumes you know the starting time and current.(4) For Dynamic acceleration, the starting current is not 100% flat during the starting time, but in Static acceleration it is flat.(5) Static acceleration is simple, Dynamic acceleration is rather complicated.3. Can we evaluate the system using Static only not dynamic?Yes. Make sure you have the correct information for motor locked rotor current and the stating time for the load.Go the ETAP tutorial site (http://www.etap.com/training/tutorials-training-videos.htm) and see the tutorial #12 (Dynamic Acceleration) and #13 (Static acceleration).curtesy msamd
Quadratic equation in real life?
One example... X = 1/2 A t2 + V0 t + X0 Where X is distance, A is acceleration, t is time, V0 is initial velocity, and X0 is initial distance. This allows you to calculate where you would be given a starting position, velocity, and acceleration, after a specified time, such as in an automobile.
Why are the Rear Wheels grabbing after acceleration?
the tires are starting to "hook up".
How do you work out velocity when given acceleration and time?
Answer: v=u + at v (Velocity) = u (Starting velocity) + a (acceleration) x t (time) So, starting from stationary (u=0), the velocity is simply a x t e.g. if the acceleration is 5mph per second per second, after 10 seconds you would be travelling at 50mph. Answer: The above is for constant acceleration. In the case of variable acceleration, integration has to be used.
