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A rock is dropped from rest and falls for 3 seconds what is the acceleration?
Wiki User
∙ 14y ago
The acceleration due to the earths gravitational field at the surface is on average about 9.8 m/s^2, or 9.8 meters per second per second. This means that every second you fall go 9.8 m/s faster. So if we ignore air-resistance we find that a rock dropped from rest will have a speed of 3s * 9.8 m/s^2 = 29,4 m/s.
Wiki User
∙ 14y ago
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A stone falls from rest how fast is it falling after 10 seconds?
Speed = (acceleration) times (time)Acceleration = gravity = 9.8 meters (32.2 feet) per second2Speed = 10g = 98 meters (322 feet) per second
What is the acceleration experienced by a car that takes 10 seconds to reach 27 meters per seconds from rest?
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
Hits a speed of 50 m s after 5 seconds what is his rate of acceleration?
If he started out from "rest" (zero speed), then his average acceleration for the 5 seconds is50/5 = 10 meters per second2
What is the distance covered by a freely falling object 5 seconds after it is dropped from rest?
0.7848 meter
What is the acceleration by a freely falling object 5 seconds after it is dropped from rest?
It depends if it is affected by air resistance or not. If not then all objects close to the surface of the Earth have an acceleration of 9.81ms^-2 in free fall. If it is affected by air resistance you need all sorts of more information to answer that question, like the drag coefficient of the air.
A stone falls from rest how fast is it falling after 10 seconds?
Speed = (acceleration) times (time)Acceleration = gravity = 9.8 meters (32.2 feet) per second2Speed = 10g = 98 meters (322 feet) per second
A 12 kg rock falls from rest off a cliff and hits the ground in 1.5 s What is the velocity?
The acceleration of gravity is 9.8 meters/sec2.In 1.5 seconds after it's dropped, any object is falling at (9.8 x 2) = 19.6 meters/sec.The mass of the rock makes no difference.
What is the average velocity of the particle from rest to 9 seconds?
The answer will depend on its acceleration.
What is the acceleration experienced by a car that takes 10 seconds to reach 27 meters per seconds from rest?
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
How far will a freely falling object dropped from rest in eight seconds?
Assuming the object free-falls, we may use:x = x0 + v0t + at2/2x0 = 0 (we determine it)v0t = 0 (dropped from rest).a = g = 10 m/st2 = 16s2.x = 10*16 / 2 = 80m.
An object is dropped from rest at a height of 128 m. Find the distance it falls during its final second in the air.?
If an object is dropped from rest at a height of 128 m, the distance it falls during its final second in the air is still 128 m.
A ball is dropped freely from rest If it travels a distance 53.9metres in the 6th second of its journey find its acceleration?
9.8
What is the distance covered by a freely falling object 5 seconds after it is dropped from rest?
0.7848 meter
Is a car accelerates from rest to 27M/S 22.9 seconds what is the average acceleration?
the acceleration of the car is 1.179m/s/s given the formula provided.
Hits a speed of 50 m s after 5 seconds what is his rate of acceleration?
If he started out from "rest" (zero speed), then his average acceleration for the 5 seconds is50/5 = 10 meters per second2
What is the acceleration of a body which starts from rest and travels 87.5 m in 5 seconds?
distance = 1/2 acceleration x time squared; acceleration is 7 m/s/s
What is the acceleration by a freely falling object 5 seconds after it is dropped from rest?
It depends if it is affected by air resistance or not. If not then all objects close to the surface of the Earth have an acceleration of 9.81ms^-2 in free fall. If it is affected by air resistance you need all sorts of more information to answer that question, like the drag coefficient of the air.
