Assuming the die is a standard die with a different number from the set {1, 2, 3, 4, 5, 6} on each side, then:
Probability_of_success = number_of_ways_of_success/total_number_of_outcomes
There is only 1 way to roll a 4 and there are 6 possible outcomes, therefore the probability of rolling a 4 is 1/6
The die has no knowledge of previous rolls; each roll is independent, thus:
The probability of three fours is a row is the probability of a 4 times the probability of a 4 times the probability of a 4, which is:
Probability = 1/6 × 1/6 × 1/6 = 1/216
The probability of rolling a number less than 6 on a die would be 5/6.
The probability is 21/36 = 7/12
The probability is 1. It is a certainty that you will roll a number between and including one and six. The probability of rolling each individual number is 1/6.
4/6
The probability is 1, if the dice are rolled often enough.
1/6
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
The probability of rolling a number less than 6 on a die would be 5/6.
The probability is 21/36 = 7/12
The probability is 1. It is a certainty that you will roll a number between and including one and six. The probability of rolling each individual number is 1/6.
1 out of 2
Because 3/6 of the sides on a number cube have even numbers, the probability of rolling even on one number cube is 1/2(equivalent of 3/6). But since you're rolling twice, you multiply the probability of one by itself (therefore rolling 2 number cubes). So: 1/2x1/2=1/4 The probability of rolling an even number when a number cube is rolled twice is 1/4, 25%, or 1 out of 4.
4/6
The probability is 1, if the dice are rolled often enough.
If the die is rolled often enough, the probability is 1. With only two rolls of a fair die, the probability is 1/6.
If you're only rolling one die, it's a probability of 1 out of six, or 16.67%.
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