The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So:
P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
I am not sure but I think 3/36
The probability that any number will come up on one cube is 1/6. 1/6*1/6=1/36 the probability is 1/36
First of all it is probability second of all the answer is 1/6+1/6 which is 2/12 which simplified is 1/6
Of all the six numbers on a cube, only the '5' is not a factor of 12.Probability of rolling a factor of 12 on the first cube = 5/6 .Probability of rolling a factor of 12 on the second cube = 5/6 .Probability of rolling a factor of 12 on both cubes = (5/6 x 5/6 ) = 25/36 = 694/9 %.
Number of possible outcomes of one cube = 6Number of possible outcomes of the other cube = 6Number of possible outcomes of two cubes = 6 x 6 = 36Number of ways to roll a sum of 7 with two cubes = 61 - 62 - 53 - 44 - 35 - 26 - 1Probability of rolling the sum of 7 = 6/36 = 1/6 = (16 and 2/3) percent
The probability is 21/36 = 7/12
If the number cubes are standard dice cubes, the odds of rolling 3 ones is 1 in 216.
Because 3/6 of the sides on a number cube have even numbers, the probability of rolling even on one number cube is 1/2(equivalent of 3/6). But since you're rolling twice, you multiply the probability of one by itself (therefore rolling 2 number cubes). So: 1/2x1/2=1/4 The probability of rolling an even number when a number cube is rolled twice is 1/4, 25%, or 1 out of 4.
It is 1.
The probability is 1/36.
The probability is 57/216 = 19/108
36
impossible
50%
On a roll of two dice, the chance of rolling a 3 (one and two) is 2 in 36, or 1 in 18 when reduced.
4/12
The probability is 5/6.