W-V percent concentration
g/mL = 1.20g/240mL = 0.005 g/mL percent
.01 M
i)NaOH + FeCl3 ii) Na2CO3 + CaCl2
Calcium chloride can absorb very much water and become a solution.
do you mean 100 ml? most solutions are given in terms of volume not mass. But ...CaCl2 has a molar mass of 111 g The hydrated form also contains 108 g water. This gives a total mass of 219 g for the hydrated form.The solution must contain: 100 g x 5% = 100 x 5/100 = 5g anhydrous CaCl25 / x = 111 / 219solve for x: x = 5(219)/111 = 9.865 g of the hydrate
The molarity is 2 mol/L.
1.00 m
The percent mv is 6.7%.
This depends of the concentration of CaCl2 in this solution.
1.83m
Volume of solution=V=240ml . Density of solution=d=1.13g/ml. Mass of solution=V*d=240*1.13=271.2g . Mass of solute=1.20g . PERCANTAGE W/W = 1.20/271.2*100=0.44%
It depends on the concentration of the solution. If you know the concentration(molarity) then use the equation. moles = [conc] x vol(mL) / 1000 NB The '1000' isusedto convert the concentration units of moles per litre (molL^-1) to mL.
CaCL2 on its own cannot have a concentration. It would have to be dissolved in a solution first. Then, from the amount of CaCl2 which is dissolved in a certain amount of a solute (such as water), you would be able to figure out the concentration.
Molarity is probably the most commonly used unit of concentration. It is the number of moles of solute per liter of solution (not necessarily the same as the volume of solvent!). Example: What is the molarity of a solution made when water is added to 11 g CaCl2 to make 100 mL of solution? Solution: 11 g CaCl2 / (110 g CaCl2 / mol CaCl2) = 0.10 mol CaCl2 100 mL x 1 L / 1000 mL = 0.10 L molarity = 0.10 mol / 0.10 L molarity = 1.0 M http://chemistry.about.com/od/lecturenotesl3/a/concentration.htm http://www.tpub.com/content/MIL-SPEC/MIL-P/MIL-P-71158/MIL-P-7115800013.htm http://www.tpub.com/content/armymedical/md0837/md08370139.htm
1.83m No srsly, it is. CaCl2 dissociates to form three ions.
.01 M
The molarity is 2,973.
The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.