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V = KQ/R

let surface charge density be sigma.

so, Q = 4pir^2.(sigma)

now, V = (r.sigma)/epsilon

epsilon = 8.854 X 10^-12 C2 N-1 m-2

outward pull = (sigma)^2/2.epsilon

=(epsilon.V^2)/2r^2

=1390 * 10-8 N/m2

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Q: A sphere of radius 10 cm is charged to a potential of 500V Calculate the outward pull per unit area?
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