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A square and a rectangle have equal areas -length of the rectangle is 9cm longer than the side of the square and the width of the rectangle is 6cm shorter than the side of the SQ- length of SQ side?
Wiki User
∙ 13y ago
Let the length of a side of the square be S.
Then the length of the rectangle = S + 9, and the width = S - 6
As the areas are equal then, S2 = (S + 9)(S - 6) = S2 +3S - 54
Thus, 3S = 54 : S = 18
The length of a side of the square is 18 cm.
Check : 182 = 324 : (18 + 9)(18 - 6) = 27 x 12 = 324
Wiki User
∙ 13y ago
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If the area of a rectangle is 18 square inches and the length of the rectangle is twice it's width what is the length and width of the rectangle?
A rectangle with one side that is double the length of the other side can be seen as two squares beside each other, that are half the area of the original rectangle, in this case 18 square inches / 2 = 9 square inches. The side of a square is the square root of the area, in this case the square root of 9 square inches, which is 3 inches. Now think about the rectangle again. What we just counted was the side of a square that made up one half of the rectangle you wanted to calculate the area of. So the shorter side of the rectangle is the same as our square, and the longer side is double the length. So the width of the rectangle is 3 inches, and the length is 2 * 3 inches = 6 inches. Or: Area = length x width (A=lw) Area = 18 (in2) Width = w Length = twice width (2w) 18 = (2w)w 18 = 2w2 9 = w2 3 = w The width is 3 in., the length (2w) is 6 in.
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