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Q: The area of a rectangle is 63 square feet the length is two feet longer than the width what is the width of the rectangle?

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The length and width can't be determined since it is a rectangle. A length would need to be given, or it would have to be a square.

Length is 11 and width is 7 and so 11 times 7 = 77 square cm

Just multiply the width and the length for a rectangle or a square. The answer is 884cm squared.

A rectangle with one side that is double the length of the other side can be seen as two squares beside each other, that are half the area of the original rectangle, in this case 18 square inches / 2 = 9 square inches. The side of a square is the square root of the area, in this case the square root of 9 square inches, which is 3 inches. Now think about the rectangle again. What we just counted was the side of a square that made up one half of the rectangle you wanted to calculate the area of. So the shorter side of the rectangle is the same as our square, and the longer side is double the length. So the width of the rectangle is 3 inches, and the length is 2 * 3 inches = 6 inches. Or: Area = length x width (A=lw) Area = 18 (in2) Width = w Length = twice width (2w) 18 = (2w)w 18 = 2w2 9 = w2 3 = w The width is 3 in., the length (2w) is 6 in.

The area of a rectangle with a width of 9 and length of 23 is 207 square units.

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