15
Call the number of nickels n and the number of dimes d. From the problem statement,
d = 2n - 12 and 0.05n + 0.10d = 2.55. Substitute the first of these equations into the second to yield 0.05n + 0.10 (2n - 12) = 2.55, or 0.05n + 0.20 n - 1.2 = 2.55, or
0.25n = 3.75; n = 3.75/0.25 = 15; d = 30 - 12 = 18.
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
there r 40 nikels
If I understand the question properly, the trick is to put the nickels on the corners. The first layer of your "box" will be all dimes, arranged like so: -00- 0--0 0--0 -00- (the -'s represent empty space and the 0's represent dimes) Let us give the dimes letters to identify them: -AB- C--D E--F -GH- Now, you want to put your four nickels on the corners, so you would place one on top of A and C, one on top of B and D, one on top of E and G, and one on top of F and H. This would look roughly like: XABX C--D E--F XGHX where the X's represent nickels. Since they are bigger than the dimes, they actually would be on top of the dimes, not on the same level. Now, every side has 30 cents, because we can count each nickel twice, as it is on the corner.
The half truckload of dimes is more valuable.If comparing the value of "half as many" dimes (10 cents) to nickels (5 cents), the value would be the same. But a "truckload," using the same type of truck, would be based on weight or volume. In either case, you have more value in the smaller, lighter dimes.The nickels are more than twice as heavy, and more than twice the volume:Nickel - 5.0 grams, volume 689 mm3Dime - 2.268 grams, volume 340 mm3
Let the number of nickels, dimes and quarters be n, d, q respectively. Then n +d + q = 30 5n + 10d + 25q = 550 But d = 2n, so: n + 2n + q = 30 => 3n + q = 30 5n + 10(2n) + 25q = 550 => 25n + 25q = 550 => n + q = 22 Which gives two simultaneous equations to solve, resulting in: n = 4, q = 18 So there are 18 quarters (plus 4 nickels and 8 dimes).
apples
There are fifteen (15) nickels.
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
You have 22 dimes and 11 pennies.
You have 22 dimes and 11 pennies.
The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?
7 quarters 2 dimes 4 nickels
In order to eliminate the decimal point, let us work with cents. So, let $ 4.50 = 450 cents. If the number of nickels is x, then the value of x nickels is 5x cents. Since the number of dimes is twice the number of nickels, then we can write the number of dimes as 2x, and the value of 2x dimes as 10(2x) or 20x cents. So we have: 5x + 20x = 450 25x = 450 divide by 25 to both sides x = 18 the number of nickels 2x = 2 x 18 2x = 36 the number of dimes Thus, Cameron has 18 nickels and 36 dimes. Check: 18 nickels = 18 x 5 cents = 90 cents or $ 0.90 36 dimes = 36 x 10 cents = 360 cents or $ 3.60 0.90 + 3.60 = 4.50? 4.50 = 4.50 True
Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?
Nickles - 10 $0.50dimes - 20 $2.00quarters - 40 $10.000.50+2.00+10.00 = $12.50 containing 40 quarters---Here's how to solve this with Algebra :Let N be the number of nickels, so that2N is the number of dimes, and2(2N) or 4N is the number of quarters.A nickel is 5 cents, a dime is 10 cents, and a quarter is 25 cents,and the total in the cash register is $12.50Multiplying by their cents values, we have5(N) plus 10(2N) plus 25 (4N) = 12505N + 20N + 100N = 1250125 N = 1250N= 10So the number of nickels is 10, dimes 20, and quarters 40.
The question is incomplete. Please post a new version with the rest of the problem.
You need to define variables for the different types of coins, write the corresponding equations, then solve them. One equation for each fact. Here are the equations:5N + 10D + 25Q = 1250 D = 2N Q = 2D