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How many coins of each type does Cameron have if he has 4.50 in nickels and dimes in his piggy bank and the number of dimes is twice the number of nickels?
In order to eliminate the decimal point, let us work with cents. So, let $ 4.50 = 450 cents.
If the number of nickels is x, then the value of x nickels is 5x cents.
Since the number of dimes is twice the number of nickels, then we can write the number of dimes as 2x, and the value of 2x dimes as 10(2x) or 20x cents.
So we have:
5x + 20x = 450
25x = 450 divide by 25 to both sides
x = 18 the number of nickels
2x = 2 x 18
2x = 36 the number of dimes
Thus, Cameron has 18 nickels and 36 dimes.
Check:
18 nickels = 18 x 5 cents = 90 cents or $ 0.90
36 dimes = 36 x 10 cents = 360 cents or $ 3.60
0.90 + 3.60 = 4.50?
4.50 = 4.50 True
What else can I help you with?
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