The acceleration of gravity is 9.8 meters (32.2 ft) per second2.
Neglecting air resistance . . .
After 8 seconds, the speed is (9.8 x 8) = 78.4 meters per second. (rounded)
After 8 seconds, the speed is (32.2 x 8) = 257.6 feet per second. (rounded)
On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get: 78.4m/s
If a stone falls from a ledge and takes 16 seconds to hit bottom, then the bottom is 1413 meters away. This assumes acceleration due to gravity of 9.81 meters per second squared, an initial velocity of zero, and no friction due to air resistance. Air resistance will decrease the distance.x = 1/2 at2 + v0t + x0
H = 1/2 g T2 = (4.9) (64) = 313.6 meters.H = 1/2g T2 = (4.9) x (8)2 = 4.9 x 64 = 313.6 meters
According to the Laws of Physics, Horizontal Velocity is unaffected by Vertical Velocity. Thus you need to first find how long it will take the stone to hit the ground. Assume: Acceleration due to gravity = 9.8 m/s^2 Velocity due to gravity = 9.8x m/s, where x is seconds Displacement due to gravity = 9.8x^2 m, where x is seconds Set Displacement = to 78.4m 78.4m = 9.8x^2 m and solve for.. x = sqrt(8) = 2 sqrt(2) Then to find displacement horizontally, multiply time*velocity horizontally distance from base of cliff = (2 sqrt(2))s * 8 m/s = 16 sqrt(2) m
Speed = (acceleration) times (time)Acceleration = gravity = 9.8 meters (32.2 feet) per second2Speed = 10g = 98 meters (322 feet) per second
78.4 m/s
490 meters
A stone falls freely from rest The total distance covered by it in the last second of its motion equals the distance covered by it in the first three seconds How long does the stone remain in air?
Velocity* v = u + at * v = 0 + 9.8 x 8 * v = 78.4 m/sDisplacement* s = ut + ½at2 * s = 0 + ½ x 9.8 x 82 * s = 4.9 x 64 * s = 313.6 m
mgh or (1/2)mv2
On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get: 78.4m/s
After just over three and a quarter seconds.
If a stone falls from a ledge and takes 16 seconds to hit bottom, then the bottom is 1413 meters away. This assumes acceleration due to gravity of 9.81 meters per second squared, an initial velocity of zero, and no friction due to air resistance. Air resistance will decrease the distance.x = 1/2 at2 + v0t + x0
Dropping a stone from a tall building is an example of acceleration due to gravity. The stone's speed will increase as it falls until it reaches terminal velocity.
When we tie a stone to a string and whirl it, it moves in a circular path.If the velocity becomes too high then the stone changes to a mass of electrons.It starts radiating energy and ultimately falls in our hand.the energy emitted by the stone is given by E = hv.Where h is Plancks constant and v is the radial velocity of the stone.
H = 1/2 g T2 = (4.9) (64) = 313.6 meters.H = 1/2g T2 = (4.9) x (8)2 = 4.9 x 64 = 313.6 meters
H = 1/2 g T2 = (4.9) (64) = 313.6 meters.H = 1/2g T2 = (4.9) x (8)2 = 4.9 x 64 = 313.6 meters