The answer: $1,000 was invested at %5. $2,500 was invested @ 8% It is done with a system of equations when "x" is a portion of $3,500 and "y" is a portion of $3,500: x + y = 3500AND .05x +.08y = 250 Use algebra and solve #2 for "x" as follows: .05x + .08y = 250 .05x = 250 - .08y x = 5000 - 1.6y plug the value of "x" into the first equation and solve for "y": 5000 - 1.6y + y = 3500 5000 - 3500 - 1.6y + y = 0 1500 - 1.6y + y = 0 1500 = 1.6y -y 1500 = .6y 2500 = y plug the value of "y" into the original equation and solve for "x" x + 2500 = 3500 x = 3500 - 2500 x = 1000 You can plug them both into the 2nd equation in the system to check it.
The annual equivalent rate is 15.5625%. The amount invested is irrelevant to calculation of the equivalent rate.
Let P be the amount of invested money. Then, .08P = 336 P = 336/.08 = 4,200
To find 8% of an amount we multiply by 0.08 So we have an amount $x: $x x 0.08 = $250 Rearranging gives $x = 250/1.08 = $3125
x = amount of money invested at 5% y = amount of money invested at 4% x=2y .05x+.04y=350 .05(2y)+.04y=350 .1y+.04y=350 .14y=350 y=$2500 x=$5000
$14,693.28
The annual equivalent rate is 15.5625%. The amount invested is irrelevant to calculation of the equivalent rate.
Let P be the amount of invested money. Then, .08P = 336 P = 336/.08 = 4,200
To find 8% of an amount we multiply by 0.08 So we have an amount $x: $x x 0.08 = $250 Rearranging gives $x = 250/1.08 = $3125
x = amount of money invested at 5% y = amount of money invested at 4% x=2y .05x+.04y=350 .05(2y)+.04y=350 .1y+.04y=350 .14y=350 y=$2500 x=$5000
y = ln(3)/ln(1.0575) = 19.65 years, approx.
$14,693.28
Find the annual amount of FICA at a 7.51% rate by computing his annual salary
1/12th of 5% because there are 12 months in a year. ANSWER:- 1/60th per cent, which is the same as 0.01667 of the amount invested.
2500
2.5 years
2500
3125