There is no way to answer correctly without knowing where the train is relative to the tunnel and the speed that the train is traveling.
Counting from the moment when the front end of the train enters the tunnel until themoment when the rear end of the train leaves the tunnel, 9 minutes will elapse.
2 hours. If the train is one mile long and going 1 mile per hour through a mile long tunnel, in one hour the train would be completely inside the tunnel, since they are the same length and the train is only going one full tunnel length(mile) per hour. It would then take another whole hour for the end of the train to leave the tunnel, bringing the train completely out of the tunnel.
2 minutes
From the time the front of the locomotive enters the tunnel . . .-- The front of the locomotive traverses the 1-mile tunnel, bringing the center of the train to the entrance.-- The center of the train traverses the 1-mile tunnel, bringing the end of the train to the entrance.-- The end of the train traverses the 1-mile tunnel.In all, the train has to travel 3 miles. At the rate of 12 mph, it takes (3/12) = 1/4 hour = 15 minutes.
for minutes and 1 sec.
If you are timing from when the train first enters the tunnel until the last car exits the tunnel, then the train would travel 2 miles during this time.So 2 mi / (15 mi/hr) = (2/15) hr * 60 (min/hr) = 8 minutes
just as a 1 cm long train takes 2 minutes for the front and the back to completely traverse the tunnel
2 hours
4 minutes
5 min
2 mintes
4 minutes. The last car on the train is the best way to think about it. That car has to travel the length of the train(1 mile) and also the length of the tunnel( also 1 mile). The total distance would be 2 miles, obviously. So if the train were traveling at 60mph it takes 1 minute to go 1 mile, but since it is going 30mph, it would take two minutes to go 1 mile.